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EastWind [94]
3 years ago
6

Find the factors of function f, and use them to complete this statement.

Mathematics
2 answers:
sp2606 [1]3 years ago
5 0

Answer:

-3, 0, 1/2, 3

Crank3 years ago
4 0

Answer:

f(x)= 2x^4 - x^3=24 -18x^2 + 9x= 45      45-24=21

Step-by-step explanation:

just multipkye that

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Which interval for the graphed function has a local
Alex

Answer:

Interval for the function has local minimum of 0 is [2,4].

Step-by-step explanation:

You need to find the local minimum of 0 in the given function's graph.

In mathematics, local minimum is a point on a graph whose value is less than all other points near it.

See that, graph value 0 is lie on the x = 3 and in interval x = 2 to x = 4

So, final answer is :

Interval for the function has local minimum of 0 is [2,4].That's the final answer.

hope it helps

5 0
3 years ago
Which statement corresponds to the values of x shown on the following number line? (Gray line is answer, dark black line is just
PSYCHO15rus [73]

Answer:

a)-4 5×<2

Step-by-step explanation:

<h3>#CarryOnLearning</h3>
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3 years ago
2+2-8-*456*7524+7+46426+*545/65/6213-543+3112+91456+210256488765454<br><br> Answer within 10 min
zvonat [6]

Answer:

My calculator said error and i tried looking it up it said error too. I'm sorry I tried, you'll have to do it by hand

Step-by-step explanation:

5 0
3 years ago
What's the answer and how do I even do this
kkurt [141]

Answer: -1

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Maya deposits $5000 into a checking account that pays 0.75% annual interest compounded monthly. What will be the balance after 8
Nana76 [90]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 0.75\%\to \frac{0.75}{100}\dotfill &0.0075\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &8 \end{cases} \\\\\\ A=5000\left(1+\frac{0.0075}{12}\right)^{12\cdot 8}\implies A=5000(1.000625)^{96}\implies A\approx 5309.08

5 0
2 years ago
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