If you mean the m^3=105, then m^6 will be
![( \sqrt[3]{105}) ^6](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B3%5D%7B105%7D%29%20%5E6)
which is 105^2 which is
11025
Answer:
14!
Step-by-step explanation:
The actual question is 2^4 + 3^2, so 2+2+2+2=8 and 3+3=6. So, 8+6= 14
Y-4X =3 ; 2x-3y=21
Y= 3+ 4x
2x -3( 3+4x)= 21
2x- 9- 12x= 21
-10x -9= 21
-10x -9+9= 21+9
-10x = 30
X= 30/-10= -3
Y= 3+4x = 3+ 4* (-3)= 3-12= -9
Answer:
You need 10 of those numbers to be whole numbers, decimals, or fractions (THESE ARE RATIONAL)
You need the other 10 of those numbers to radicals, or numbers similar to pi (THESE ARE IRRATIONAL)
Step-by-step explanation:
