Can you help me out here im in the test rn

Artyom0805 [142]

This type of combination problem involves combined probability, or the chance that a specific set could be chosen based on the probability of multiple variables.

The number that could be generated follows the example:

XXYZZZZ

where X describes a letter, and Y describes a number that isn’t zero, and Z describes any number.

Two probabilities exist in this situation, depending on the circumstances of the question. By pressing any number once, only 8 letters can be used (ten digits, minus the one and two keys, since they don’t have letters). This means that the probability of this event is:

8 x 8 x 9 x 10 x 10 x 10 x 10

where the two eights are for the letters, the nine is for the digit that isn’t zero, and the tens are for any numbers from the keypad. This permutation yields 5,760,000 choices.

If you are allowed to press the numbers more than once to generate a letter, then the probability changes to account for the entire alphabet. The new probability of this event is :

26 x 26 x 9 x 10 x 10 x 10 x 10

where this permutation yields 60,840,000 choices.

Hope this helps!

5 0

3 years ago

Darius flipped a coin 500 times and it landed heads up 300 times. What is the relative frequency of the coin landing heads up ba

astra-53 [7]

3/5 times. in reality it should have landed 250 times as in an ideal world you get 50/50 odds of getting one side or the other

7 0

4 years ago

Read 2 more answers

a teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te

natka813 [3]

The question is incomplete. The complete question is

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shown in the below-mentioned figure shows the results of the test.

Which class should get the reward, and why?

- The 2nd-period class should get the reward. They have the highest score, a perfect 100.

- The 2nd-period class should get the reward. They have a higher median.

- The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

- The 4th-period class should get the reward. Their lowest score is an outlier and should be thrown out.

The box plot shown in the question provides the information that
In 2nd period the minimum of the data is 77, first quartile is 78, median of the data is 89, third quartile is 92 and the maximum of the data is 100.
Hence, the mean of the results of 2nd period is

$\frac{77+78+89+92+100}{5}=87.2$

In 2nd period the minimum of the data is 72, first quartile is 83, median of the data is 89, third quartile is 96 and the maximum of the data is 98.

Hence, the mean of the results of the 4th period is

$\frac{72+83+89+96+98}{5}=87.6$

Hence, obviously, the 4th period is having more mean.

Moreover, we can observe that if more of the marks are on the higher side the average will automatically be more. Hence, as the first and the third quartiles are more on the 4th-period, so the average marks for the 4th period must be better.

So, just by observing the box plot, we can give the statement that "The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class. "

Therefore, the 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

Learn more about box plots here-

brainly.com/question/1523909

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