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BARSIC [14]
3 years ago
7

Which of the following is a factor of 7x2 + 42x - 49 x2 + 49 x+7 X-7 x+ 1

Mathematics
1 answer:
Goryan [66]3 years ago
6 0

Answer:

x + 7

is the answer because 7×2+42x-49

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Which equation is equivalent to <br> f(x) =-4(x+7)^2-6
Vladimir [108]

Answer:

-4x-34

Step-by-step explanation:=−4x+−28+−6

=(−4x)+(−28+−6)

=−4x+−34

3 0
3 years ago
Help quick pleaseeee
ehidna [41]

Answer:

x= 3.096

Step-by-step explanation:

divide both sides by 5: 3^(x-1)= 10

then take the log to get log_3 (10) = x-1 = 2.096

x= 3.096

4 0
2 years ago
Simplify: 20(1/5x - 3/4)+9x
Goryan [66]

Simplified answer is: 13x - 15

7 0
3 years ago
Read 2 more answers
Some students were asked what kinds of animals they have at home.
Nataly_w [17]

(a) Animals by popularity; Dogs, Cats, Others, Horses.

(b) If 250 students were interviewed, 20 students have other pets.

(c) No, it was incorrect.

Step-by-step explanation:

Step 1; We arrange the different pets in chronological order, from the highest percent to the lowest percent;

1. Dogs - 67%,

2. Cats - 20%

3. Others - 8%,

4. Horses - 1%.

None is not included in this list.

Step 2; If 250 students were interviewed, 8% of those have other pets. So we need to calculate how much 8% of 250 is.

8% of 250 = \frac{8}{100} × 250 = 0.08 × 250 = 20.

So 20 students had other pets.

Step 3; 20% of the interviewed students had cats. If 75 students had cats, we need to equate 20% to the 75 and find out how many students were actually interviewed.

20% × x = 75, 0.2 × x = 75,

x = \frac{75}{0.2} = 375.

So if 375 students were interviewed, 75 students would have cats. So the estimate of 250 students being interviewed is incorrect.

8 0
3 years ago
Factor out the coefficient of the variable 5/6s+2/3
DochEvi [55]
Okay. so I'm gonna assume you know what factor out means--were gonna take out 5/6. what we need to know is, how does that affect our ending number 2/3? well, we're gonna have 5/6 times some stuff first off, right?

5/6 ( )

so what's in the parenthesis? well, if we distribute in our mind, S would just have to be by itself for it to work out. so we have

5/6 ( s )

but what about 2/3? well, if we're multiplying everything on the inside by 5/6, how can be get it to cancel and leave 2/3 alone? we could divide 2/3 by 5/6, right?

5/6 ( s + (2/3) / (5/6) )

now, when we distribute our 5/6, we'll have just 2/3 at the end. now let's simplify that end term so it looks a little better. if we divide by a fracion, that's the same as multiplying by the flipped version, so let's do that.

2/3 / 5/6 = 2/3 × 6/5 = 2 (6) / 5 (3) = 12/15

we can reduce 12/15 by dividing the top and bottom by three.

= 4/5

so our final answer would be:

5/6 [S + 4/5] you can redistribute to make sure it matches. Anyway, hope that helps!
6 0
3 years ago
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