Question

If sin(t) = 3/5 and t is in the 2nd quadrant, find cos(t).

Answer 1

Cosine is $\frac{hypotenuse}{adjacent}$.

Apply the equation:

$sin(t) = \frac{3}{5} \\3^2 + b^2 = 5^2\\b^2 = 5^2 - 3^2\\\\\sqrt{b^2} = \sqrt{5^2}- \sqrt{3^2}\\\\\\b = 5 - 3 \\\\b = 2$

B is the adjacent side so

cosine is:

Cos(t) = 5/2

Have a great day,

And I hope this helps you!