Answer:
a) Time to live field
b) Destination
c) Yes, they have two ip addresses.
d) 128 bits
e) 32 hexadecimal digits
Explanation:
a) the time to live field (TTL) indicates how long a packet can survive in a network and whether the packet should be discarded. The TTL is filled to limit the number of packets passing through N routers.
b) When a large datagram is fragmented into multiple smaller datagrams, they are reassembled at the destination into a single large datagram before beung passed to the next layer.
c) Yes, each router has a unique IP address that can be used to identify it. Each router has two IP addresses, each assigned to the wide area network interface and the local area network interface.
d) IPv6 addresses are represented by eight our characters hexadecimal numbers. Each hexadecimal number have 16 bits making a total of 128 bits (8 × 16)
e) IPv6 address has 32 hexadecimal digits with 4 bits/hex digit
Answer:
oid changeCase (char char_array[], int array_size ) {
__asm{
mov eax, char_array;
mov edi, 0;
readArray:
cmp edi, array_size;
jge exit;
mov ebx, edi;
shl ebx, 2;
mov cl, [eax + ebx];
check:
//working on it
cmp cl, 0x41;
jl next_indx;
cmp cl, 0x7A;
jg next_indx;
cmp cl, 'a';
jl convert_down;
jge convert_up;
convert_down:
or cl, 0x20; //make it lowercase
jmp write;
convert_up:
and cl, 0x20;
jmp write;
write:
mov byte ptr [eax + ebx], cl
next_indx:
inc edi;
exit:
cmp edi, array_size;
jl readArray;
mov char_array, eax;
}
}
Explanation:
- Move char_array to eax as it is base image
.
- Use ebx as offset
.
- Use ecx as the storage register
.
- check if cl is <= than ASCII value 65 (A)
.
Answer: Package software
Explanation:
Packaged software is the software that contains the functions and programs that are similar in the nature and features.
It is designed in such a way so that it can attract the customers and user by providing the benefit of the selling of the collection of programs rather than buying individual software programs which costs higher.
Thus, it produced at a large scale as well as bought by numerous users.
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
