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dangina [55]
3 years ago
6

To protect a computer, it is a good idea to install and frequently run

Computers and Technology
2 answers:
Triss [41]3 years ago
5 0

Answer:

anti virus software

Explanation

did the quiz :)

maxonik [38]3 years ago
5 0

Answer:

anti-virus software

Explanation:

Got it right on my edgenuity test

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Your computer is taking longer than usual to open files and you notice that your hard drive light stays on longer than usual. Wh
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There might be insufficient storage space so your computer usually takes a longer time to load.The bigger your file, the longer it takes to load. So the solution is to clear up your storage space



7 0
3 years ago
Given a floating-point formal with a k-bit exponent and an n-bit (fraction, write formulas for the exponent E, significant M, th
ANEK [815]

Answer:

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112  ≈ 7/4

fractional value ( F )  = 0.112

And, numeric value of the quantity ( V )  = 7

The exponent bits will be represented  as :  100----01.

while The fraction bits will be represented  as : 1100---0.

<u>B) The largest odd integer that can be represented exactly </u>

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

=  1.11------12 = 2 - 2-n

also the fractional value ( F ) =  

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits  will be represented  as follows:  n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

<u>C) The reciprocal of the smallest positive normalized value </u>

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E )  = 2k-1 – 2

While the significand value ( M )  = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

Explanation:

E = integer value of exponent

M = significand value

F = fractional value

V = numeric value of quantity

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112  ≈ 7/4

fractional value ( F )  = 0.112

And, numeric value of the quantity ( V )  = 7

The exponent bits will be represented  as :  100----01.

while The fraction bits will be represented  as : 1100---0.

<u>B) The largest odd integer that can be represented exactly </u>

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

=  1.11------12 = 2 - 2-n

also the fractional value ( F ) =  

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits  will be represented  as follows:  n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

<u>C) The reciprocal of the smallest positive normalized value </u>

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E )  = 2k-1 – 2

While the significand value ( M )  = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

8 0
3 years ago
Suppose you have two RAID arrays, one implementing RAID 3, the other RAID 5. Each has 9 disk drives in its array. If the RAID 5
Snezhnost [94]

Answer:

48 is the answer

Explanation:

16×3 is the explanation for your question

8 0
3 years ago
Fern has set up a computer network for the entire building. Unfortunately, the signal strength diminishes as it reaches toward t
stepladder [879]

Answer:

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Explanation:

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5 0
2 years ago
java Consider the following problem statement. A cookie recipe calls for the following ingredients: 1.5 cups of sugar 1 cup of b
Veronika [31]

Answer:

Explanation:

The following code is written in Java. It creates a program that asks the user how many cookies they want to make. Then it adjusts the original recipe based on the ratio of the original amount of cookies it makes to the amount the user wants. Finally, passing the output of the new adjusted recipe to the user. Due to technical difficulties, I have added the code as a txt file attached below.

4 0
3 years ago
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