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4 years ago

What is the probability that a randomly selected number from 15-27 is prime?

1 answer:

8 0

Answer: As we know that, Probability of an event =Number of favourable cases Number of total cases, We get, probability of choosing a prime number from 1 to 20 =820=25. Therefore, we get the probability of choosing a prime number from 1 to 20 as 25or 0.4.

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option (b) and (d) are correct.

Right triangle J K L with right angle at K. J K is 60 centimeters. J L is 68 centimeters. K L is 32 centimeters.

and Right triangle D E F with right angle at E. D E is 22.5 centimeters. D F is 25.5 centimeters. E F is 12 centimeters.

Step-by-step explanation:

Given : triangle a b c where angle b is a right angle. side a b is 15 cm. side b c is 8 cm. side a c is 17 cm.

We have to select triangle from given options that are similar to ΔABC,

Two triangles are said to be similar when their corresponding sides are in same ratios and their corresponding angles are equal.

Consider : Right triangle J K L with right angle at K. J K is 60 centimeters. J L is 68 centimeters. K L is 32 centimeters.

FINDING CORRESPONDING RATIOS,

$\frac{AB}{JK}=\frac{15}{60}=\frac{1}{4}$

$\frac{BC}{KL}=\frac{8}{32}=\frac{1}{4}$

$\frac{AC}{JL}=\frac{17}{68}=\frac{1}{4}$

Since, ratios are equal. Thus, triangles are similar.

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Consider : Right triangle D E F with right angle at E. D E is 22.5 centimeters. D F is 25.5 centimeters. E F is 12 centimeters.

FINDING CORRESPONDING RATIOS,

$\frac{AB}{DE}=\frac{15}{22.5}=\frac{2}{3}$

$\frac{BC}{EF}=\frac{8}{12}=\frac{2}{3}$

$\frac{AC}{DF}=\frac{17}{25.5}=\frac{2}{3}$

Since, ratios are equal. Thus, triangles are similar.

ΔABC ≅ ΔDEF

Thus, option (b) and (d) are correct.

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What is the probability that a randomly selected number from 15-27 is prime?​

What is the probability that a randomly selected number from 15-27 is prime?