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yKpoI14uk [10]
3 years ago
12

Help y’all

Mathematics
2 answers:
Cloud [144]3 years ago
6 0

Answer:

DID YOU GET AN ANSWER???

Step-by-step explanation:

plz tell me what is was

Ugo [173]3 years ago
4 0

Answer:

The answer is 201

Step-by-step explanation:

the equation used is (b-a)/2=?

To get the answer, we plug in the info we have which is

a=61

?=70

we use inverse operation to get b

(b-61)/2=70

b-61=140

b=201

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How do I find a2 and a3 for the following geometric sequence? 54, a2, a3, 128
vlada-n [284]
The formula for the nth term of a geometric sequence:
a_n=a_1 \times r^{n-1}
a₁ - the first term, r - the common ratio

54, a_2, a_3, 128 \\ \\
a_1=54 \\
a_4=128 \\ \\
a_n=a_1 \times r^{n-1} \\
a_4=a_1 \times r^3 \\
128=54 \times r^3 \\
\frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\
\frac{64}{27}=r^3 \\
\sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\
\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\
r=\frac{4}{3}

a_2=a_1 \times r= 54 \times \frac{4}{3}=18 \times 4=72 \\
a_3=a_2 \times r=72 \times \frac{4}{3}=24 \times 4=96 \\ \\
\boxed{a_2=72, a_3=96}
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Step-by-step explanation:

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