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3 years ago

PLS HELP ASAP I DONT HAVE TIME FOR THIS, IT ALSO DETECTS IF ITS RIGHT IR WRONG

Mathematics

1 answer:

kodGreya [7K]3 years ago

4 0

Answer:

It's 130

Step-by-step explanation:

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Can you help me with this ?

lubasha [3.4K]

Answer:
200 petals
Proportionality is 50

3 0

3 years ago

Calculate the expression below. Use the correct<br> order of operations.<br> 3x (4 - 2) + 1

Ivanshal [37]

Answer: 7

Step-by-step explanation:

3x (4 - 2) + 1

3x (2) + 1

6 + 1

6 0

3 years ago

If yk please help thank you

ryzh [129]

Answer: No real solution

Step-by-step explanation:

5 0

3 years ago

9. A band director wants to form a committee of 4 parents from a list of 45 band parents.

Alex73 [517]

Answer:

Part (A): The number of ways to select 12 jurors are 86493225.

Part (B): The number of ways to select 2 alternates are 306.

Part (C): Part (a) is an example of combination and Part (a) is an example of permutation

Step-by-step explanation:

Consider the provided information.

A band director wants to form a committee of 4 parents from a list of 45 band parents.

Part (A): How many different groups of 4 parents can the band director select?

Since order doesn't matter so we will use combination.

Use the formula for combination $^{n}C_{r}=\frac{n!}{r!(n-r)!}$

Substitute n=45 and r=4 in above formula.

$^{45}C_{4}=\frac{45!}{4!(45-4)!}$

$^{45}C_{4}=\frac{45!}{4!41!}$

$^{45}C_{4}=148995$

Hence, the number of ways are 148995.

Part (B) How many different ways can the band director select 4 parents to serve in the band parents’ association as president, vice president, treasurer, and secretary?

Since the order matter so we will use permutation:

The formula for permutation is: $^{n}P_{r}=\frac{n!}{(n-r)!}$

Substitute n=45 and r=4 in above formula.

$^{45}P_{4}=\frac{45!}{(45-4)!}$

$^{45}P_{4}=\frac{45!}{41!}$

$^{45}P_{4}=3575880$

Hence, the number of ways are 3575880.

Part (C) . Explain the difference between parts (a) and (b) in terms of how you decided to solve each part.

Part (A) is an example of number of combination where order doesn't matter.

Part (B) is an example of permutation where order matter.

7 0

3 years ago

An auto license plate consists of 6 digits; the first three are any letter (from the 26 alphabets), and the last three are any n

tamaranim1 [39]

Answer: There are 17576000 ways to generate different license plates.

Step-by-step explanation:

Since we have given that

Numbers are given = 0 to 9 = 10 numbers

Number of letters = 26

We need to generate the license plate numbers.

Since there are repetition allowed.

We would use "Fundamental theorem of counting".

So, the number of different license numbers may be created as given as

$26\times 26\times 26\times 10\times 10\times 10\\\\=26^3\times 10^3\\\\=17576\times 1000\\\\=17576000$

Hence, there are 17576000 ways to generate different license plates.

7 0

4 years ago