4 - 2 3/5<br>please simplify

The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$

So the correct option is 4

8 0

3 years ago

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A square pyramid has a base with side lengths each measuring 40 inches. The pyramid is 21 inches tall, with a slant height of 29

Alchen [17]

Answer

Find out the what is the surface area of the pyramid .

To proof

Formula

Surface area of a square pyramid

$= a^{2} + 2a \sqrt{\frac{a^{2}}{4} +h^{2}$

Where a is the base edge and h be the height .

As given

A square pyramid has a base with side lengths each measuring 40 inches. The pyramid is 21 inches tall, with a slant height of 29 inches.

i.e Base edge = 40 inches

Height = 21 inches

Put values in the above formula

$= 40^{2} + 2\times40\times\sqrt{\frac{40^{2}}{4} +21^{2}$

solving

$= 1600 + 80 \sqrt{\frac{1600}{4} + 441$

$= 1600 + 80\times\sqrt{841}$

$\sqrt{841} = 29$

= 1600 + 80 × 29

= 3920 inches²

Therefore the surface area of the pyramid is 3,920 inches²

Hence proved

4 0

2 years ago

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Is 3/20 larger then 2

aleksley [76]

To find out is 3/20 is larger than 2 we will convert 3/20 to a decimal. Lets do it:-

3/20
3 ÷ 20 = 0.15

Is 0.15 larger than 2?

No, 0.15 is not larger than 2.

So, 3/20 isn't larger than 2.

Hope I helped ya!! xD

8 0

3 years ago

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The gross domestic product (GDP) of a certain country, which measures the overall size of the economy in billions of dollars, ca

DiKsa [7]

Answer:

The estimated GDP in 2007 is 12782 billion dollars.

The estimated GDP in 2011 is 15010 billion dollars.

The estimated GDP in 2012 is 15567 billion dollars.

Step-by-step explanation:

Consider the provided function.

$g(y) = 557y +8883$

Where y = 10 corresponds to the year 2010.

Part (b) Estimate the GDP (to the nearest billion dollars) in 2007.

If y = 10 corresponds to the year 2010 then y = 7 corresponds to the year 2007.

Substitute the value of y = 7 in the provided function.

$g(y) = 557(7) +8883$

$g(y) = 3899+8883$

$g(y) = 12782$

Hence, the estimated GDP in 2007 is 12782 billion dollars.

Part (b) Estimate the GDP (to the nearest billion dollars) in 2011.

If y = 10 corresponds to the year 2010 then y = 11 corresponds to the year 2011.

Substitute the value of y = 11 in the provided function.

$g(y) = 557(11) +8883$

$g(y) = 6127+8883$

$g(y) = 15010$

Hence, the estimated GDP in 2011 is 15010 billion dollars.

Part (C) Estimate the GDP (to the nearest billion dollars) in 2012.

If y = 10 corresponds to the year 2010 then y = 12 corresponds to the year 2012.

Substitute the value of y = 12 in the provided function.

$g(y) = 557(12) +8883$

$g(y) = 6684+8883$

$g(y) = 15567$

Hence, the estimated GDP in 2012 is 15567 billion dollars.

4 0

3 years ago

A nugget of gold is placed in a graduated cylinder that contains 85 mL of water.the water level rises to 225 mL after the nugget

Rufina [12.5K]

To get the volume of an object, one of the oldest techniques is to fill a container with water of which we know the volume (in this case 85mL), and drop the object in. The water will rise and show a new volume (225mL). If we subtract the old volume (85) from the new volume (225), we will get the volume of the object (225 - 85 = 140).

8 0

3 years ago

4 - 2 3/5please simplify​

4 - 2 3/5please simplify