All categories

4 years ago

5. Find x if √x=79.

Mathematics

2 answers:

Anna11 [10]4 years ago

7 0

Answer:

6241

Step-by-step explanation:

hope this is correct

Jet001 [13]4 years ago

5 0

Answer:

x=6241

Step-by-step explanation:

^2 on both sides.

x=79^2.

x=6241.

Hope this helps plz hit the crown :D

You might be interested in

Cot^4θ-4cot^2θ-5=0 <br>solve for θ

stich3 [128]

$\cot^4\theta-4\cot^2\theta-5=(\cot^2\theta-5)(\cot^2\theta+1)=0$

$\cot^2\theta-5=0\implies\cot^2\theta=5\implies\cot\theta=\pm\sqrt5$

Recall that $\cot\theta=\cot(\theta+\pi)$ , which is to say $\cot x$ has period $\pi$ . This in turn means that $\cot\theta=0$ will have the same solutions as $\cot(\theta+n\pi)=0$ for any integer $n$ . So the general solution to the first case is

$\cot\theta=\pm\sqrt5\implies\theta=\cot^{-1}(\pm\sqrt5)+n\pi$

where $n$ is any integer.

On the other hand,

$\cot^2\theta+1=0\implies\cot^2\theta=-1$

but $x^2\ge0$ for any value of $x$ , so this equation has no (real) solutions for $\theta$ .

4 0

3 years ago

Help please someone I need all answers please

snow_tiger [21]

17. 8/10 is equal to .8 not .08
18a. False
18b. True
18c. False
18d. False
18e. True
19. 0.02
20. No, the zero needs to be in the tenths place or else the decimal (.2) would become 2/10.
21. 17/100
22. Words- Ten hundredths
Fraction- 10/100
Decimal- .10

5 0

4 years ago

If the sales are $680 and the commission rate is 9% what is the commission

Scrat [10]

Answer:

61.2

Step-by-step explanation:

6 0

4 years ago

Select the graph that represents two quantities in a proportional relationship

Goshia [24]

Answer:

Step-by-step explanation:

That is the proportional relationship. It Starts at 0. It could be wrong though.

6 0

3 years ago

Read 2 more answers

Simply 6-4 root 3/ 6+4 root 3 by ratnolising the denominator

Inessa [10]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

the question asks us to rationalise the given expression !

so let's start ~

$\frac{6 - 4 \sqrt{3} }{6 + 4 \sqrt{3} } \\ \\ \implies \: \frac{6 - 4 \sqrt{3} }{6 + 4 \sqrt{3} } \: \times \: \frac{6 - 4 \sqrt{3} }{6 - 4 \sqrt{3} } = \frac{(6 - 4 \sqrt{3}) {}^{2} }{6 {}^{2} - 4 \sqrt{3} {}^{2} } \\ \\ \implies \frac{\: 6 {}^{2} + 4 \sqrt{3} {}^{2} - (2 \times 6 \times 4 \sqrt{3} )}{36 - 48} \\ \\ \implies \: \frac{36 + 48 - 48 \sqrt{3} }{ - 12} \\ \\ \implies \: \frac{84 + 48 \sqrt{3} }{ - 12} \\ \\ \implies \: \frac{ \cancel{- 12}(7 - 4 \sqrt{3} )}{ \cancel{ - 12} } \\ \\ \implies \: 7 - 4 \sqrt{3}$

hope helpful :D

3 0

2 years ago

Read 2 more answers

5. Find x if √x=79. ​

5. Find x if √x=79.