Question

One positive number exceeds another by 2, and their product is 80. Find the numbers​

Answer 1

Answer:

The Answer is: The first number is 10 and the second number is 8.

Step-by-step explanation:

Let f = first number and s = second number.

The first number is 2 larger than the second:

f = n + 2

The numbers times each other is 80:

f * n = 80

Substitute the value of f, which is (n + 2):

n(n + 2) = 80

n^2 + 2n = 80

n^2 + 2n - 80 = 0

(n + 10)(n - 8) = 0

n^2 + 10n - 8n - 80 = 0, so the first number is 10 and the second one is 8.

Another method, just from thinking about it:

factor 80:

8 * 10, is the first factoring I thought of. I then noted that the difference between the two is 2 and if you multiply them they equal 80.

Hope this helps! Have an Awesome Day!! :-)