Answer:
an = 6 +5(n-1)
an = 1 +5n
Step-by-step explanation:
The equation for an arithmetic term is
an =a1 +d(n-1)
where a1 is the 1st term and d is the common difference
an = 6 +5(n-1)
We can distribute the 5
an = 6+5n-5
an = 1 +5n
Answer:
B
Step-by-step explanation:
D. Because Ram only did 2 hours so then that makes 2 hours of work done but then left for whatever reason. Ajit left 3 hours BEFORE the completion of the work and that gives us info that there were hours put in between both Rams and Ajits work. They all started at the same time so it doesn't mean that Ajit didn't do any of the work. Ajit can work for 12 hours POSSIBLY. It did not say he can exact. So it leaves to Suresh that can work up to 15 hours of the work but we dont know how long he did it. Suresh either could just gone over or less than 15 hours.
Answer:
0.0133
Step-by-step explanation:
Set up the long division.
225 | 3
2 Calculate 300 ÷ 225, which is 1 with a remainder of 75.
0 . 01
_____
225 | 3.
2 . 25
__
75
3 Bring down 0, so that 750 is large enough to be divided by 225.
0 . 01
_____
225 | 3.
2 . 25
__
750
4 Calculate 750 ÷ 225, which is 3 with a remainder of 75.
0 . 013
______
225 | 3.
2.25
__
750
675
___
75
5 Bring down 0, so that 750 is large enough to be divided by 225.
0. 0 1 3
_______
225 | 3.
2.25
__
750
675
_____
75
6 Calculate 750 ÷ 225, which is 3 with a remainder of 75.
0 . 0133
_______
225 | 3.
2. 25
__
750
675
___
750
675
___
75
7 Therefore, 3 ÷ 225 ≈ 0.0133.
Answer: 0.0133