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Vlad1618 [11]
3 years ago
14

CH4(g) + 2O2(g) = CO2(g) + 2H2O(g)

Chemistry
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

0.04 moles of CH₄  are required

Explanation:

Given data:

Number of moles of CH₄ required = ?

Number of moles of O₂ present = 0.08 mol

Solution:

Chemical equation:

CH₄ + 2O₂     →   CO₂ + 2H₂O      

now we will compare the moles of oxygen and methane.

                      O₂          :        CH₄

                       2           :           1

                     0.08        :        1/2×0.08 = 0.04

Thus, 0.04 moles of CH₄  are required.

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Answer : Volume of HCl ( in ml)  is 10 ml.

Solution : Given,   Concentration of NaOH = 0.1 mol/L

                                Volume of NaOH = 20 ml

                                Concentration of HCl = 0.2 mol/L

                                 Volume of HCl =  ?

    Formula used :   Moles = Volume ×  Concentration

    In the reaction, we see that 1 mole of NaOH react with the 1 mole of HCl.

    so,

                       Moles of NaOH = Moles of HCl

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    Converstion ml into L :      1000 ml = 1 L

             Moles of HCl =  \frac{20}{1000} × 0.1

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                                       =  0.01 L

             Volume of HCl (in ml) =  0.01 × 1000 = 10 ml



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