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Vlad1618 [11]
3 years ago
14

CH4(g) + 2O2(g) = CO2(g) + 2H2O(g)

Chemistry
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

0.04 moles of CH₄  are required

Explanation:

Given data:

Number of moles of CH₄ required = ?

Number of moles of O₂ present = 0.08 mol

Solution:

Chemical equation:

CH₄ + 2O₂     →   CO₂ + 2H₂O      

now we will compare the moles of oxygen and methane.

                      O₂          :        CH₄

                       2           :           1

                     0.08        :        1/2×0.08 = 0.04

Thus, 0.04 moles of CH₄  are required.

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Convert 1.45 × 1024 atoms of carbon to moles of carbon.
anygoal [31]
1 mol = 6.02 * 10^23 atoms of carbon
x mol = 1.45 * 10^24 atoms of carbon

1/x =6.02*10^23 / 1.45 * 10^24

6.02 * 10^23 x = 1.45 * 10^24
x = 1.45 * 10^24 / 6.02 * 10^23
x = 2.41 mols of carbon
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#1. Which one of the following statements correctly defines active site? The active site is a site on the enzyme molecule where
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Analyze complete and balance the following equation co2(g)+hcl(aq)
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Answer:

CO_{2} (g)+4HCl(aq)->2H_{2} O(g)+CCl_{4} (g)

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Material property of glass
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Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop
Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

                     Mg  +   Cu(NO₃)₂    ⇒    Mg(NO₃)₂   +   Cu

                  Reactants           Elements            Products

                         1                          Mg                     1

                         1                          Cu                      1

                         2                          N                       2

                         6                          O                       6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

                                              = 24 + 28 + 96

                                              = 148 g

                           24 g of Mg  --------------------  148 g of Mg(NO₃)₂

                          147.4 g of Mg -------------------   x

                            x = (147.4 x 148) / 24

                            x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = \frac{actual yield}{theoretical yield}

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = \frac{30.8}{100} x 908.96

Actual yield = 279.95 ≈ 280g

                     

4 0
3 years ago
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