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Paraphin [41]
3 years ago
7

If the calcium oxide were to be obtained by the heating of calcium hydroxide, how much hydroxide would be needed to obtain the 1

5.0 g?
Chemistry
1 answer:
Sidana [21]3 years ago
7 0
Ca(OH)2 -------> CaO + H2O
ratio is 1 : 1
CaO Mr= 56g
15/56 = 0.268 mol (mols of CaO in 15g)
Ca(OH)2 Mr= 74g
0.268x74= 19.83g (required amount of Cash(OH)2)




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Molarity of 0.50 mol sugar in 270 mL of solution.
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<h3>Answer:</h3>

1.85 M

<h3>Explanation:</h3>

<u>We are given;</u>

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But, 1000 mL = 1 L

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We are required to calculate the molarity of the solution;

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Molarity = Moles ÷ Volume

In this case;

Molarity = 0.50 moles ÷ 0.27 L

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5 0
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Extend your thinking: The slow decay of radioactive materials can be used to find the age of rocks, fossils, and archaeological
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The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

<h3>What is the half-life of a radioactive material?</h3>

The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.

The half-life, t_\frac{1}{2}, the age, t, and amount remaining, A_{r}, of a radioactive material are related by the formula below:

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For the Egyptian papyrus with 63% of its original carbon-14 atoms:t = \frac{6000*0.63}{-0.63} = 4000\:years

For the Aboriginal charcoal with 22% of its original carbon-14 atoms:

t = \frac{6000*0.22}{-0.63} = 13106.5\:years

For the Mayan headdress with 79% of its original carbon-14 atoms:

t = \frac{6000*0.79}{-0.63} = 2040\:years

Neanderthal skull with 3% of its original carbon-14 atoms:

t = \frac{6000*0.03}{-0.63} = 30353\:years

Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

Learn more about half-life at: brainly.com/question/26689704

#SPJ1

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