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jarptica [38.1K]
3 years ago
13

Okay this is not school related but how do you not fall for some one so hard .

Chemistry
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

Love is not only the thing in this world!

Study hard, you can choose a better way of life.

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1. What does it mean for a substance to be soluble?​
Anni [7]

Answer:

Solubility is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. ... Certain substances are soluble in all proportions with a given solvent, such as ethanol in water.

Explanation:

3 0
4 years ago
Read 2 more answers
How many liters are in 5.42 mols of O2 gas?<br><br> (2 decimal places)
Debora [2.8K]

Explanation:

1 mol = 22.4 l

5.42 mol = 22.4 × 5.42 = 121.408

in two decimal place it is 121.41

7 0
3 years ago
Qual é o principal fator que indica que o organismo está adptado?
Hoochie [10]

Answer:

Explanation:

Any genetically based physiological, behavioral, or ecological trait that enables an organism to cope with, and to survive and reproduce in, its environment represents an adaptation.

Qualquer traço fisiológico, comportamental ou ecológico de base genética que permite a um organismo enfrentar, sobreviver e se reproduzir em seu ambiente representa uma adaptação.

5 0
3 years ago
A 1.59 mol sample of Kr has a volume of 641 mL. How many moles of Kr are in a 4.41 L sample at the same temperature and pressure
Marina86 [1]

Answer:

The correct answer is 10.939 mol ≅ 10.94 mol

Explanation:

According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).

For the initial gas (1), we have:

n₁= 1.59 mol

V₁= 641 mL= 0.641 L

For the final gas (2), we have:

V₂: 4.41 L

The relation between 1 and 2 is given by:

n₁/V₁ = n₂/V₂

We calculate n₂ as follows:

n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol

5 0
3 years ago
Give examples of how low and high levels of radiation can each be helpful.
Paraphin [41]
Visible light
Microwaves
Low frequency waves
Radio waves
Remote controls
Cordless phones
And so on!
Hope this is helpfull! :D
~Korey
8 0
3 years ago
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