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devlian [24]
2 years ago
7

What is the empirical formula for a compound that contains 10.89% magnesium 31.77% chloride and 57.34% oxygen

Chemistry
1 answer:
Blizzard [7]2 years ago
4 0

Answer: Mg_{1}Cl_{2}O_{8}

Explanation:

If percentage are given then we are taking total mass is 100 grams.So, the mass of each element is equal to the percentage given.

Mass of Mg = 10.89 g

Mass of Cl = 31.77 g

Mass of O = 57.34 g

Step 1 : convert given masses into moles.

Moles of Mg=\frac {\text{ given mass of Mg}}{\text{ molar mass of Mg}}= \frac {10.89g}{24g/mole}=0.45moles

Moles of Cl = \frac {\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac {31.77g}{35.5g/mole}=0.89moles

Moles of O =\frac {\text{ given mass of O}}{\text{ molar mass of O}}=\frac {57.34g}{16g/mole}=3.58moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Mg = \frac {0.45}{0.45}=1

For Cl = \frac {0.89}{0.45}=2

For O= \frac {3.58}{0.45}=8

The ratio of Mg :Cl : O= 1 : 2 : 8

Hence the empirical formula is Mg_{1}Cl_{2}O_{8}

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Carbon tetrachloride would be 2.2 fold heavier than water

Explanation:

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2 years ago
How do neutral metal atoms form ions?​
stira [4]

Answer:

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4 0
3 years ago
What is a metalloid?
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8 0
3 years ago
Sodium is much more apt to exist as a cation than chlorine because:
8090 [49]

Answer:

(D) chlorine has a greater ionization energy than sodium

Explanation:

Sodium is the element of the group 1 and period 3 which means that the valence electronic configuration is [Ne]3s^1.

Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is [Ne]3s^23p^5.

Ionization energy is the minimum amount of energy which is required to knock out the loosely bound valence electron from the isolated gaseous atom.

<u>Thus, removal of one electron in sodium is easy as it will gain noble gas configuration and become stable. But this case does not exist in chlorine and hence, chlorine has a greater ionization energy than sodium.</u>

So,

Sodium is much more apt to exist as a cation than chlorine because chlorine has a greater ionization energy than sodium.

7 0
3 years ago
How many mL of 4.0% Mg(NO3)2 solution would contain 1.2 g of magnesium nitrate?
galina1969 [7]
4.0 % in mass per volume :

4.0 g ---------- 100 mL
1.2 g ----------  ( volume )

Volume =  1.2 x 100 / 4.0

Volume = 120 / 4.0

= 30 mL

hope this helps!
8 0
3 years ago
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