The answer is: " -21 " .
__________________________________________
We are asked to solve for: "6t" ; which is: "6 * t" .
__________________________________________
Given: 3t − 7 = 5t ; Solve for "t" ; then solve for "6t" ;
3t − 7 = 5t ; Subtract "3t" from each side of the equation;
____________________________________________
3t − 7 − 3t = 5t − 3t ;
to get: -7 = 2t ;
Divide EACH side of the equation by "2" ; to isolate "t" on one side of the equation; and to solve for "t" ;
-7/2 = 2t / 2 ;
-3.5 = t ; ↔ t = - 3.5 ;
____________________________________________
Now, solve for "6t" ;
6 t = 6*(-3.5) = - 21 . The answer is: " -21 " .
____________________________________________
Answer:
D
Step-by-step explanation:
This isnt a cartisean coordinate plane so A is wrong. One of our points is at

Because it coincide with real number 3, and negative imaginary number i.
Conjugates are terms with opposite inverse of terms.
So our conjugates is

Answer:
add 6 unit tiles
Step-by-step explanation:
The square is completed when the algebra tile grid pattern is a square. This one will be a square when 6 more unit tiles are added to fill the empty spaces at the bottom right.
9514 1404 393
Answer:
A. 3×3
B. [0, 1, 5]
C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.
Step-by-step explanation:
A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.
This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...
A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)
Matrix A is 3×3.
__
B. The second row of A represents the second equation:

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.
__
C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)
Answer:
26
Step-by-step explanation:
Let x represent the missing number

Convert both fractions to improper fractions

Cross multiply


Subtract both sides by 1,575


Divide both sides by 15

x = 26