I need help in stw with twine peaks ssd's tell me ur epic and so u can help me

pickupchik [31]

Answer:

The answer is:

$\frac{6r-5q}{r^2-q^2}$

which agrees with the last answer option (D) in the list.

Step-by-step explanation:

In order to add rational expressions, we need to express them with the same denominator. Therefore we examine what factors there are in the first denominator, which happens to be a difference of squares which is readily factored out as:

$r^2-q^2=(r+q)\,(r-q)$

the second denominator consists of only one of these factors: $(r+q)$ , then in order to express both rational expressions with the same common denominator, we multiply numerator and denominator of the second fraction by the factor: $(r-q)$

Then we get two expressions that can be easily added as shown below:

$\frac{r}{(r+q)\,(r-q)} +\frac{5\,(r-q)}{(r+q)\,(r-q)} =\frac{r+5(r-q)}{(r+q)(r-q)} =\frac{r+5r-5q}{(r+q)\,(r-q)} =\frac{6r-5q}{r^2-q^2}$

7 0

3 years ago

Using the table below, what is Xavier's take-home pay?

damaskus [11]

Answer:

b

Step-by-step explanation:

6400+2448+1600+75=10523

32,000-10523=21477

7 0

3 years ago

Read 2 more answers

Someone please help me

ludmilkaskok [199]

Volume=s to the third power
2 1/2 to the third power is 15.625 inches
The answer is 15.625 inches

3 0

3 years ago

Write a linear function f with the given values. f(0) = 2. f(2) = 4

Ganezh [65]

Answer:

I Think this will be the answer, We need to write the equation of a line with the given values of $f(0)=2$ and $f(2)=4$. To write the equation of the line, we can use the slope-intercept ...

Step-by-step explanation:

give brainiest

6 0

3 years ago

Volumes I to IV of "Famous Mathematicians" are sitting in numerical order between two bookends on a table. Each cover of a volum

Rama09 [41]

We want to find the distance between the first page of the first book in a collection and the last page of that collection.

We will get that the distance is 13cm

Let's see how to solve this:

We know that:

Each cover is 0.5cm thick
The pages (all of them) for each volume are 5cm thick.

We want to find the distance between the first page of the first volume and the last page of the last volume.

Because we go from the first page of the first volume to the last page of the last volume, we will ignore the first cover and pages of the first volume and the pages and back cover of the last volume.

We ignore the pages because in normal book positioning, the first page will be on the right side of the book (and the last page is on the left side), and if we order the books from left to right, then we can ignore all the other pages of book I and book IV.

Then we have:

one cover for volume 1.
two covers and pages for volume 2
two covers and pages for volume 3
one cover for volume 4.

Now we just need to add all the correspondent measures:

( 0.5cm) + (5cm + 2*0.5cm) + (5cm + 2*0.5cm) + ( 0.5cm) = 13cm

Then the distance between the page 1 of volume I and last page of volume IV is 13cm.

If you want to learn more, you can read:

brainly.com/question/12082741

3 0

2 years ago