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3 years ago

What is the repeating digit of 4/9

Mathematics

2 answers:

Sonja [21]3 years ago

8 0

Its 0.4 and the 4 repeats infinitely :)

Burka [1]3 years ago

6 0

13 and brown and green orange orange

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What is the volume of 22.5 g of metal with a density of 2.81 g/cm

xz_007 [3.2K]

Answer:V = 72.1 cm³ - 50.0 cm³ = 22.1 cm³

D = mV=99.7g22.1cm³ = 4.51 g/cm³

Step-by-step explanation:

d = mV

m = d×V

V = md

DENSITY

Density is defined as mass per unit volume.

d = mV

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d = mV = 433g200cm³ = 2.16 g/cm³

MASS

d = mV

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL × 1.11g1mL = 555 g

VOLUME

d = mV

We can rearrange this to get the expression for the volume.

V = md

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg × 1000g1kg = 14 830 g

Step 2: Calculate the volume.

V = md = 14 830 g × 1cm³19.32g = 767.6 cm³

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4 years ago

21 2/3 Divided by 3 1/4

kirill [66]

Answer:6.66666666667

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the Volume of the square pyramid? (Round to the nearest tenth as needed)

Orlov [11]

<h3><u>given</u><u>:</u></h3>

base= 25 mm

height= 28 mm

the volume of the square pyramid.

<h3><u>solution</u><u>:</u></h3>

<u> $volume = {a}^{2} \frac{h}{3}$ </u>

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2 years ago

Don works in home construction. He determined that the function t(A)=144A/9.252 gives the total number of 9 in. tiles needed to

Oksanka [162]

Answer:

6,226 tiles of 9 in are needed to cover an area of 400 square feet

Step-by-step explanation:

Let

A -----> an area in square feet

t(A) ---> the total number of 9 in. tiles needed

we have

$t(A)=\frac{144A}{9.252}$

For A=400 ft^2

substitute in the equation and solve for t

$t(400)=\frac{144(400)}{9.252}$

$t(400)=6,226\ tiles$

That means -----> 6,226 tiles of 9 in are needed to cover an area of 400 square feet

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