1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hitman42 [59]
2 years ago
14

There are 6 fourth-grade students, 8 fifth-grade students, and 10 sixth-grade students on the girls’ soccer team at Truman Eleme

ntary School. What is the ratio of all students to fourth-grade students? Use a proportion to solve.
Mathematics
1 answer:
enyata [817]2 years ago
7 0

Answer:

Your answer is

Fourth grade student = 25%

Fifth grade= 33.33%

Sixth grade= 41.67%

Want more answer then follow me, like and MARK MY ANSWER AS BRAINLIST ANSWER.

I need that urgently.

You might be interested in
The number of new cars purchased in a city can be modeled by the equation C=20t to the 2nd power, where C is the number of new c
Allisa [31]

Answer:

1998 + 5\sqrt{30}

Step-by-step explanation:

Set up the equation:

Since C(t) gives the number of cars purchased in the t-th year after 1998, then make the number of cars equal to 15 000 and solve for t - the year:

20t^2 = 15000

t^2 = 750

t = \sqrt{750} = \sqrt{10} \cdot \sqrt{25} \cdot \sqrt{3} = 5\sqrt{30}

The year will be simply 1998 + 5 \sqrt{30}

4 0
3 years ago
Help me substitution method define variables
Rina8888 [55]
\left \{ {{S=14+L} (I) \atop {S+L=124}(II)} \right.

<span>Substitute (I) into (II), we have:
</span>S+L=124
(14+L)+L=124
14 + 2L = 124
2L = 124 - 14
2L = 110
L =  \frac{110}{2}
\boxed{L = 55}

<span>Replace (II) in (I), we have:
</span>S=14+L
S = 14+ 55
\boxed{S = 69}

Answer:
each student sell: 
Lori = 55 pizzas
Steve = 69 pizzas
<span>

</span>
7 0
3 years ago
URGENT!! WILL MARK BRAINLIEST IF CORRECT!!!
kow [346]

Answer:

Story 2 because it is talking about how much they spend. ANOTHER HINT: That equation has all the numbers in story 2. They key is to look at how the problem is set up.

6 0
3 years ago
A jar contains 45 red candies and 60 black candies. Suppose a candy is selected at random. What are the odds against selecting a
uysha [10]

Answer:

3:4.

Step-by-step explanation:

To work this out we need to find the highest multiple of 45 and 60.

15 is the largest number that goes into both of them so what we are going to do now is divide both number by 15.

45 divided by 15 = 3

60 divided by 15 = 4

Therefore the odds of selecting a red candy is 3:4.

Hope that helps. x

7 0
2 years ago
B) Tyler swam 32 laps in the pool. Kevin swam 3 times as many laps as Tyler. Lets the number of
evablogger [386]

If Tyler did 32 laps and Kevin did 3 times that amount; its quite simple, you would find three times the amount of Tylers laps which is 96.

4 0
2 years ago
Read 2 more answers
Other questions:
  • Y=4x+1 <br> Do x and y vary directly?
    15·1 answer
  • What is an equation equal -x^2-36
    15·1 answer
  • 2 doctors is _______% of 25 doctors
    15·1 answer
  • Is the GCF of 28 and 50
    8·2 answers
  • A number cube with six sides is rolled seven times. The probability of getting a 4 exactly twice is ____
    11·1 answer
  • The sales tax is ​$50 on the purchase of a dining room set for ​$1000. Find the sales tax rate.
    6·1 answer
  • This is due tomorrow, so please help and show step by step​
    9·1 answer
  • I don’t understand this do any of you do?
    14·1 answer
  • Twice a year, the P.E. teachers test the fitness level of all sixth-grade students at Walker Middle School. The students' weight
    14·1 answer
  • 1) Evaluate the expression 3^3 • (12 – 2) = 2.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!