<em>y</em> - 1/<em>z</em> = 1 ==> <em>y</em> = 1 + 1/<em>z</em>
<em>z</em> - 1/<em>x</em> = 1 ==> <em>z</em> = 1 + 1/<em>x</em>
==> <em>y</em> = 1 + 1/(1 + 1/<em>x</em>) = 1 + <em>x</em>/(<em>x</em> + 1) = (2<em>x</em> + 1)/(<em>x</em> + 1)
<em>x</em> - 1/<em>y</em> = <em>x</em> - (<em>x</em> + 1)/(2<em>x</em> + 1) = (2<em>x</em> ² - 1)/(2<em>x</em> + 1) = 1
==> 2<em>x</em> ² - 1 = 2<em>x</em> + 1
==> 2<em>x</em> ² - 2<em>x</em> - 2 = 0
==> <em>x</em> ² - <em>x</em> - 1 = 0
==> <em>x</em> = (1 ± √5)/2
If you start solving for <em>z</em>, then for <em>x</em>, then for <em>y</em>, you would get the same equation as above (with <em>y</em> in place of <em>x</em>), and the same thing happens if you solve for <em>x</em>, then <em>y</em>, then <em>z</em>. So it turns out that <em>x</em> = <em>y</em> = <em>z</em>.
The elevation represents a distance from the sea level greater than 5 feet,
because the original description specifies a distance greater than 5 feet
below sea level.
Reasons:
The elevation given as a distance is the height or distance above sea level.
In the above description, elevation is a vector, given that it has both
magnitude (distance) and direction (above sea level).
Distance is a scalar quantity, that has only a magnitude that specifies the
space covered during motion.
An elevation of less than -5 feet indicates that distance of the location
above sea level is less than -5 feet, which is the same as; the distance of
the location below sea level is greater than 5 feet.
- Less than -5 feet above sea level = Greater than 5 feet below sea level
Therefore;
- An elevation of less than -5 feet represents a distance from (below) sea level greater than 5 feet
Learn more about vector and scalar quantities here:
brainly.com/question/11968679
The inverse is (x + 10)/3
When the base is greater than 1, the value approaches zero as the exponent goes to -∞. When the base is less than 1, the value approaches zero as the exponent goes to ∞. Whatever additions or factors you have that modify the exponential term will modify the asymptote accordingly.
