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pochemuha
3 years ago
13

Jack wants to use a circular rug on his rectangular office floor to cover two small circular stains, each less than π/100 square

feet in area and each more than 3 feet from the nearest wall. Can the rug be placed to cover both stains ?(1) Jack's rug covers an area of 9π square feet.(2) The centers of the stains are less than 4 feet apart.
Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer: YES

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • Area of each stain=less than π/100 square feet  
  • Each one 3 feet from the nearest wall
  • Area of rug: 9π square feet
  • The centers of the stains are less than 4 feet apart.

First, we have to apply the formula AREA OF A CIRCLE(A)= π r², to obtain the radius of each stain:

π/100 = π r²  

π/100 (1/ π)= π r²  

1/100 = r²

√1/100 =r

r = 1/10 ⇒ radius of each stain

The centers of the stains are less than 4 feet apart, so:

Max diameter needed to cover is 4+ 1/10 + 1/10 = 21/5 = 4.2

Finally, we have to obtain the diameter of the rug to compare:

Area of rug: 9π

: 9π = π r2 ⇒ r= 3  

⇒ d (diameter)= 3 x2 = 6 ft

With statements (1) and (2), we know that the diameter of the rug (6ft) can completely cover both stains (max distance is 4 .2ft)

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Answer:

252

Step-by-step explanation:

9 x 28 = (9 x 20) + (9 x 8)

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9 x 8 = 72

180 + 72 = 252

9 x 28 = 252

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Step-by-step explanation:

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Step-by-step explanation:

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My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

8 0
3 years ago
Need help with number 1.
seropon [69]

Answer:

Your answer is E.

Step-by-step explanation:

8 0
4 years ago
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