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4 years ago

In June, the price of a pair of inline skates is $165. The price changes each of the next 3 months.

Mathematics

1 answer:

Natasha2012 [34]4 years ago

8 0

Answer:

july: $153 august: $155 september: $156

Step-by-step explanation:

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A town has a population of 5000 and grows at 3.5% every year. What will be the population after 15 years, to the nearest whole n

RUDIKE [14]

Answer: 7,625

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A tire has a diameter of 184 cm what is the circumference of the tire

viktelen [127]

Here is your answer

diameter of tyre= 184cm

So,

Circumference= $\:{pi}$ ×d

= 3.14 × 184 cm

= 577.76 cm

HOPE IT IS USEFUL

8 0

3 years ago

an 8 in. by 10 in. photo is reduced so that the width (the shorter dimension) is 3 in. what is the length of the reduced photo

Sindrei [870]

Answer:

Step-by-step explanation:

The length can be found by setting up a proportion. If the width is reduced by some ratio, then the length will share the same ratio.

3 / 8 = x / 10 Multiply both sides by 10.

3 * 10 / 8 = x Multiply first

30/8 = x Divide next. You don't need to do it in this order.

3 6/8 Simplify

3 3/4 Give another choice

3.75

The length = 3.75 inches

If none of these are correct, please leave a note with your choices.

6 0

4 years ago

Simplify 22x-13y+19-17y-43x+12

erma4kov [3.2K]

Answer:

-21x-30y+31

Step-by-step explanation:

7 0

4 years ago

Let c be the curve of intersection of the parabolic cylinder x2 = 2y, and the surface 3z = xy. find the exact length of c from t

Mandarinka [93]

Parameterize the intersection by setting $x(t)=t$ , so that

$x^2=2y\iff y=\dfrac{x^2}2\implies y(t)=\dfrac{t^2}2$
$3z=xy\iff z=\dfrac{xy}3\implies z(t)=\dfrac{t^3}6$

The length of the path $C$ is then given by the line integral along $C$ ,

$\displaystyle\int_C\mathrm dS$

where $\mathrm dS=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt$ . We have

$\dfrac{\mathrm dx}{\mathrm dt}=1$
$\dfrac{\mathrm dy}{\mathrm dt}=t$
$\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{t^2}2$

and so the line integral is

$\displaystyle\int_{t=0}^{t=2}\sqrt{1^2+t^2+\dfrac{t^4}4}\,\mathrm dt$

This result is fortuitous, since we can write

$1+t^2+\dfrac{t^4}4=\dfrac14(t^4+4t^2+4)=\dfrac{(t^2+2)^2}4=\left(\dfrac{t^2+2}2\right)^2$

and so the integral reduces to

$\displaystyle\int_{t=0}^{t=2}\frac{t^2+2}2\,\mathrm dt=\dfrac{10}3$

3 0

3 years ago