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weqwewe [10]
3 years ago
8

The formula for the area of a square is s2, where s is the side length of the square. What is the

Mathematics
1 answer:
arlik [135]3 years ago
8 0

Answer:

36

Step-by-step explanation:

Area of a square is s² , where 's' is the side length.

For a square of side length = 6 cm ,

The area = (6 cm)² = 36 cm²

<em>* Why did your teacher say that you should not include units in your answer?</em>

<em />

Anyway, the area without units is 36 .

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Just 7 i really dont want to do the work 3
leonid [27]

Answer:

267

Step-by-step explanation:

3 0
3 years ago
What is the height of a cylinder with volume 6,908 cubic feet and with a radius of 10 feet? (Round to the nearest integer)
Eduardwww [97]
21.99 but rounds to 22
4 0
3 years ago
Una empreza tiene contratadas 75 personas. En las oficinas trabaja el 16% de los hombres y 20% de mujeres, si el total de person
andrew11 [14]

Answer:

50 hombres y 25 mujeres

Step-by-step explanation:

Sea m el número de hombres y w el número de mujeres.

El total es 75

Así; m + w = ​​75 •••••••• (i)

Además; 16% de m + 20% de w = 13

0,16 m + 0,2 w = 13

Multiplicar por 100

16m + 20w = 1300 ••••• (ii)

De i, m = 75-w 16 (75-w) + 20w = 1300

1200 - 16w + 20w = 1300

4w = 1300-1200

w = 100/4 w = 25

Recordar; w + m = 75

25 + m = 75

m = 75-25

m = 50

6 0
3 years ago
What's a real number between -1/10 and 0?
vova2212 [387]

Answer:

The answer is at the bottom!!

Step-by-step explanation:

And All of those Natural Numbers will be starting with 1 so we will be having other Numbers as well on which No Number will be mapped like 2 or 211 or 79 So This Means Set of Natural Numbers is Grater then Real Numbers Between 0 and 1. So Set of Real Numbers Between 0 and 1 is Countably Infinite.

Hope this helps!!

4 0
3 years ago
In the equation 9^2 x 27^3 = 3^x, what is the value of x? <br> Show your work on scratchpaper
IceJOKER [234]

Answer:

x=13

Step-by-step explanation:

9^2 * 27^3 = 3^x

We need to get each term with a base of 3

9^2 = (3^2) ^2

We know that a^b^c = a^(b*c)

(3^2) ^2 = 3^(2+2) = 3^4

27^3 = (3^3) ^3 = 3^(3*3) = 3^9

Replacing these in the original equation

3^4 * 3^9 = 3^x

We know that a^b *a^c = a^(b+c)

3^4 * 3^9  =3^(4+9) = 3^13 = 3^x

The bases are the same, so the exponents must be the same

x=13

7 0
3 years ago
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