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weqwewe [10]
3 years ago
8

The formula for the area of a square is s2, where s is the side length of the square. What is the

Mathematics
1 answer:
arlik [135]3 years ago
8 0

Answer:

36

Step-by-step explanation:

Area of a square is s² , where 's' is the side length.

For a square of side length = 6 cm ,

The area = (6 cm)² = 36 cm²

<em>* Why did your teacher say that you should not include units in your answer?</em>

<em />

Anyway, the area without units is 36 .

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Answer: 1 is 1,3

Step-by-step explanation:

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Jen wrote ten times as many pages of a school report as tom. They wrote 396 pages altogether. How many pages did each student wr
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Let pages written by Tom for a school report = x

Pages written by Jen for school report= 10 x

Pages written by Tom + Pages written by Jen = 396

→ x  + 10 x = 396

→ 11 x =396

Dividing both sides by 11, we get

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3 years ago
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natulia [17]

Answer:

77 m (nearest metre)

Step-by-step explanation:

<u>Angle of Elevation</u>

If a person stands at a point and looks up at an object, the angle between their <u>horizontal line of sight</u> and the <u>object</u> is called the angle of elevation.

To find how tall the flagpole is, model as a right triangle and solve using the tan trigonometric ratio.

<u>Tan trigonometric ratio</u>

  \sf \\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given information:

  • Person height = 1.6 m
  • Horizontal distance (from person to flagpole) = 35 m
  • Angle of elevation = 65°

Therefore:

  • \theta = 65°
  • O = height of flagpole <u>less</u> height of person
  • A = 35 m

As the person is 1.6 m tall, we model the line of sight as 1.6 m <u>above ground level</u>.  Therefore, when calculating the height of the flagpole, we will need to add the height of the person to the value found using the trig ratio.

Substitute the given values into the formula and solve for O:

\implies \sf \tan(65^{\circ})=\dfrac{O}{35}

\implies \sf O=35\tan(65^{\circ})

Therefore the height of the flagpole is:

\implies \sf 35\tan(65^{\circ})+1.6=76.65774222...

\implies \sf Height\:of\:flagpole=77\:m\:(nearest\:metre)

Learn more about Angles of Elevation here:

brainly.com/question/27933160

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