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3 years ago

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Sarah’s neighbor offers to pay her $5 for every shark tooth she finds on the beach. After collecting only three shark’s teeth, S

arah decides to share the opportunity with her friend John. Sarah can find shark teeth twice as fast as John, but she can earn even more money with his help.
Sarah can use the expression 5(2j + 3 + j) to represent the amount of money she can earn.

others had no helpful answers,, ##

2 answers:

Vaselesa [24]3 years ago

4 0

Answer:

=15j+15

Step-by-step explanation:

blsea [12.9K]3 years ago

4 0

Answer:

Here are some expressions you could use!

<em>15j + 15</em>

<em>or</em>

<em>5(2j + 3 + j)</em>

<em>or</em>

<em>25(10j + 18 + 5j)</em>

<em>or</em>

<em>4(5j + 8 + 4j)</em>

<em>or</em>

<em>10(4j + 6 + 2j)</em>

All of these are right you can choose which one to use! 25(10j + 18 + 5j) is the easiest one to solve in my opinion.

<u><em>~ LadyBrain</em></u>

You might be interested in

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

4 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

5 0

3 years ago

PLEASE HELP ME I NEED THIS RIGHT NOW

pav-90 [236]

Answer:

The answer is the second one

(-4, 0)

6 0

3 years ago

Read 2 more answers

Given the graph below, which of the following statements is true?

nirvana33 [79]

Answer:

D) The graph does not represent a one-to-one function because the y-values between 0 to 2 are paired with multiple x-values.

Step-by-step explanation:

Let's find the ordered pairs.

(-4, 4), (-3, 2), (-2, 0), (-1, 0.5), (0, 1), (1, 1.5), (2, 2), (3, 0)

The graph passed through above points.

In the x-coordinates -3, 2 gives the same output. Therefore, the given function is not one-to-one.

Therefore, the answer D)

The graph does not represent a one-to-one function because the y-values between 0 to 2 are paired with multiple x-values.

Hope you will understand the concept.

Thank you.

7 0

3 years ago

How many pt are there in 10 qt

nataly862011 [7]

The answer is 20 pt. Hope this helped

8 0

3 years ago