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olganol [36]
2 years ago
10

Solve the system by graphing ​

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
4 0
Where is the picture?
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What single decimal multiplier would you use to decrease by 12% followed by a 4% increase
vagabundo [1.1K]

Answer:

The single decimal multiplier is 0.9152

Step-by-step explanation:

Here, we want to write a single decimal number that would work as to decrease an original value by 12% and increase it also by 4%

Let the original value be x

12% = 12/100 = 0.12

So decreasing by 12% would be x-0.12x = 0.88x

Now this 0.88x, we shall increase it by 4%

4% is same as 0.04

Thus by increasing , we have;

0.88x + 0.04(0.88x)

= 0.88x + 0.0352x = 0.9152x

So the single factor we are multiplying by is 0.9152

3 0
3 years ago
Can someone tell me how to solve this
Butoxors [25]
X squared+y=18
x+y=6. use elimination method.(+y and +y cancels 
x squared -x=x
18-6=12
x=12
for y take one of the above equations
x+y=6(replace x with 12
12+y=6(collect the like terms
y=6-12
y=-6

so x=12 and y=-6
6 0
3 years ago
Monique spends $28 and buys a pair of socks and a headband for each day of the week each headband costs $2.50 and all the cost t
pav-90 [236]

Answer:

$10.50 is spent on socks

Step-by-step explanation:

for 7 days, monique would spend $17.50 on headbands and $10.50 on socks.

7 0
3 years ago
Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

In which E_{1},E_{2} and E_{3} are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

6*0.050mg = 0.30mg of levonorgestrel and 6*0.030mg = 0.18mg of ethinyl estradiol are taken.

So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

So L_{2} = 0.375 and E_{2} = 0.20

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0
3 years ago
A classroom has the dimensions shown the dimensions are the length which is 9.1 the width which is 10.3 and the height which is
melisa1 [442]
Area is 93.73

Volume is 299.36

Area of all 4 walls is 116.48
6 0
3 years ago
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