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3 years ago

PLZ HELP I NEED THIS TODAY! Choices are:

Mathematics

2 answers:

Charra [1.4K]3 years ago

5 0

Answer:

C. The volume of the cylinder is about 25 cubic inches greater than the volume of the cone.

Step-by-step explanation:

The volume of a cone = $\frac{pi*r^2*h}{3}$ and the volume of a cylinder = πr²h

(cone vol = 201.06 in³ and cylinder vol=226.19in³)

Nuetrik [128]3 years ago

3 0

Answer:

I think is C

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Answer:

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Step-by-step explanation:

width×Length

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2 years ago

50 points! Mhanifa please help! I would appreciate it! Random answers will be reported!

alisha [4.7K]

Answer:

x = 4, ∠I = 33°

Step-by-step explanation:

Question 1

Converse to Base Angles Theorem: 28 = 9x - 8,

28 = 9x - 8 (add 8 to both sides)

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Question 2

Since the triangles are congruent, ∠A ≅ ∠G:

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2 years ago

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11/3 is equal to 3 2/3

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3 years ago

A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro

pshichka [43]

Answer:

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed $\frac{dx}{dt}$ = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=(x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=rx$

$\frac{dh}{dt}=\frac{rx}{h}$

When automobile is 30 miles past the intersection,

For x = 30

$\frac{dh}{dt}=\frac{30r}{h}$

Since $h=\sqrt{d^{2}+(30)^{2}}$

Therefore,

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}$

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

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3 years ago

How many solutions does y=−2x−4 y=3x+3 have

Wewaii [24]

Answer:

There is one solution

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