Answer:
3
Step-by-step explanation:
Because it is factor of the expression
<em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>a</em><em>d</em><em>i</em><em>u</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>q</em><em>u</em><em>e</em><em>s</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>2</em><em>5</em><em>p</em><em>i</em>
There is no common ratio or common difference. The first three terms increases more slowly than a cubic, but the last three increase more quickly than the cube of n. The pattern is not obvious to me. When the sequence is cast in recursive terms, you get
... a[n] = (48/13)a[n-2] + (59/39)a[n-1] . . . . a[1] = 2, a[2] = 9
The next term using this rule is 174 34/39, not an integer.
The coefficients p and q for a[n-2] and a[n-1] can be found from
![2p+9q=21\\9p+21q=65](https://tex.z-dn.net/?f=2p%2B9q%3D21%5C%5C9p%2B21q%3D65)
_____
Any sequence of 4 numbers can be matched by a polynomial of degree 3 or less. Here, a calculator's polynomial regression function tells us the rule could be
... a[n] = 4.5n³ -24.5n² +49n -27
Using this rule, the next two terms are 168 and 357.
Answer:
The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.
This value of Δy is not constant for a constant increase in production.
Step-by-step explanation:
We know that the production function is
, and in the current situation
and
.
With this information we can calculate the actual budget level:
![p_0 = 10x^{0.2} y^{0.8}\\\\1200=10*130^{0.2} y^{0.8}\\\\1200=26.47*y^{0.8}\\\\y=(1200/26.47)^{1/0.8}=45.33^{1.25}=117.62](https://tex.z-dn.net/?f=p_0%20%3D%2010x%5E%7B0.2%7D%20y%5E%7B0.8%7D%5C%5C%5C%5C1200%3D10%2A130%5E%7B0.2%7D%20y%5E%7B0.8%7D%5C%5C%5C%5C1200%3D26.47%2Ay%5E%7B0.8%7D%5C%5C%5C%5Cy%3D%281200%2F26.47%29%5E%7B1%2F0.8%7D%3D45.33%5E%7B1.25%7D%3D117.62)
The next year, with an increase in demand of 100 more automobiles, the production will be
.
If we calculate y for this new situation, we have:
![y_1=(\frac{p_1}{10x^{0.2}} )^{1.25}=(\frac{1300}{26.47} )^{1.25}=49.10^{1.25}=130](https://tex.z-dn.net/?f=y_1%3D%28%5Cfrac%7Bp_1%7D%7B10x%5E%7B0.2%7D%7D%20%29%5E%7B1.25%7D%3D%28%5Cfrac%7B1300%7D%7B26.47%7D%20%29%5E%7B1.25%7D%3D49.10%5E%7B1.25%7D%3D130)
The budget for the following year is 130.
The variation needed for the daily buget to follow the increase in production for the first year is 12.38 $/year.
![\Delta y=y_1-y_0=130.00-117.62=12.38](https://tex.z-dn.net/?f=%5CDelta%20y%3Dy_1-y_0%3D130.00-117.62%3D12.38)
This value of Δy is not constant for a constant increase in production.
Answer:
46.875
Step-by-step explanation:
A= l x w x h so you multiple all three numbers together and get your answer