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3 years ago

What is the median of the lower half of the data 5,8,10,1,7,6,15,8,6

Mathematics

2 answers:

Degger [83]3 years ago

5 0

I’m think it is the median

Lostsunrise [7]3 years ago

3 0

Answer: 8

Step-by-step explanation:

Order from least to greatest 1,5,6,6,7,8,8,10,15, and then find the number in the middle. The number in the middle is 8

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Match each value with its formula for ABC.

MariettaO [177]

The solution to the question is:

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

<h3>What is cosine rule?</h3>

it is used to relate the three sides of a triangle with the angle facing one of its sides.

The square of the side facing the included angle is equal to the some of the squares of the other sides and the product of twice the other two sides and the cosine of the included angle.

Analysis:

If c is the side facing the included angle C, then

$c^{2}$ = $a^{2}$ + $b^{2}$ -2ab cos C-----------------1

then c = $\sqrt{a^{2} + b^{2} -2abcosC }$

if b is the side facing the included angle B, then

$b^{2}$ = $a^{2}$ + $c^{2}$ -2accosB-----------------2

b = $\sqrt{a^{2} + c^{2} -2accosB }$

from equation 2, make cosB the subject of equation

2ac cosB = $a^{2}$ + $c^{2}$ - $b^{2}$

cosB = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

if a is the side facing the included angle A, then

$a^{2}$ = $b^{2}$ + $c^{2}$ -2bccosA--------------------3

a = $\sqrt{b^{2} + c^{2} -2bccosA }$

from equation 3, making cosA subject of the equation

2bcosA = $b^{2}$ + $c^{2}$ - $a^{2}$

cosA = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

from equation 1, making cos C the subject

2abcosC = $b^{2}$ + $a^{2}$ - $c^{2}$

cos C = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

In conclusion,

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

Learn more about cosine rule: brainly.com/question/4372174

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4 0

2 years ago

What ate the coordinates of the fourth point that could be connected with (-8, 0), (1,0), and (1-5)

Gnesinka [82]

Well you can find out by the question it's pretty easy....

you have to find the same x coordinates and then see what the difference is in the y coordinate. For example, (1,0), and (1,-5) the difference is -5. So for (-8,0), and (1,0) your answer would be (8,-5)

4 0

3 years ago

Find the minimum distance between the point (-3,2) and the line y = -x + 1

Natasha2012 [34]

The minimum distance between the point(-3,2) and the line y = -x + 1 is $\sqrt{2}$ units.

<h3>What is a line segment?</h3>

The line that joins two points on a cartesian plane is a line segment.

Analysis:

The formula for calculating distance between a line and a point is

d = $\frac{Ax1 + By1 + c}{\sqrt{A^{2} + B^{2} } }$

where A = coefficient of x term of the line, B = coefficient of y in the line and C is the constant term of the line.

x1 and y1 are coordinates of the point.

for the line y = -x + 1 which is = y + x -1 = 0, A = 1, B = 1, C = -1, x1 = -3, y = 2
d = $\frac{1(-3) + 1(2) + (-1)}{\sqrt{(-3)^{2} + 2^{2} } }$ = $\sqrt{2}$ units

In conclusion, the distance between the point and the line is $\sqrt{2}$ units

Learn more about distance between line segments: brainly.com/question/2437195

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Hatshy [7]

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3 years ago

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Slav-nsk [51]

Answer:

8:30 am

Step-by-step explanation:

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3 years ago