Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
If the temperature dropped by 7.f each hour from 5:00 am to 9:00 am. the beginning temperature at 5:00 am if the temperature at 9:00 am was -10.f is 18.f.
<h3>
Beginning temperature</h3>
Dropped in temperature=7.t
Number of hours= 5:00 am to 9:00 am=4 hours
Temperature at 9:00 am=-10.f
Hence:
Beginning temperature can be calculated as:
Beginning temperature=(4× 7) + (-10)
Beginning temperature=28 + (-10)
Beginning temperature= 18.f
Check:
Since temperature dropped by 7.f each hour from 5:00 am to 9:00 am
which implies that temperature 7.f dropped for 4 hours.
Hence:
18-7-7-7-7=-10.f
Therefore If the temperature dropped by 7.f each hour from 5:00 am to 9:00 am. the beginning temperature at 5:00 am if the temperature at 9:00 am was -10.f is 18.f.
Learn more about Beginning temperature here:brainly.com/question/24746268
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Answer:
square root of,10,end square root is between 2.52.52,point,5and333
