The garden area is maximum when the enclosure is a square.
If a is the length of the side of the square then the length of the building is also a.
The perimeter length is 4a made up of 81+a feet, so 81+a=4a and 3a=81 making a=27 feet.
Ok so first, you need to figure out the change in elevation for each after one min. so we will write it as a ratio
10:-160 20:-300
So for the 10 min one, we will divide both sides by 10
1:-16 So the change in elevation per min. is -16
Now for the 20 one, we will divide by 20.
1: -15 So the change in elevation per min. is 15
So, the 10 min section of the walk the change of elevation was greater. Hope that helps! if you need me to explain something just ask!
<span />
Answer:
19ft
Step-by-step explanation:
Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.
The velocity of the ball is zero at maximum height and it is expressed as:
V(x) = dy/dx
V(x) = -32x+32
Since v(x) = 0
0 = -32x+32
32x = 32
x = 32/32
x = 1s
Get the height y
Recall that y = -16x² + 32x + 3.
Substitute x = 1
y = -16(1)²+32(1)+3
y = -16+32+3
y = -16+35
y = 19ft
Hence the maximum height reached by the ball is 19ft
This is the answer: log_5(d^4 * k^12)
Answer:
Step-by-step explanation:
The given equation is :
We need to solve it using inverse operations.
Subtract 5 from both sides of the equation.
So, the solution of the given equation is .
