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Irina18 [472]
3 years ago
11

Leonardo is solving the equation 4 (x minus one-fifth) = 2 and two-thirds. His work is shown. Where is his error? 4 (x minus one

-fifth) = 2 and two-thirds. Step 1, 4 x minus four-fifths = 2 and two-thirds. Step 2, 4 x = StartFraction 8 over 3 EndFraction + four-fifths. Step 3, 4 x StartFraction 40 over 15 EndFraction + StartFraction 16 over 15 EndFraction. Step 4, 4 x = StartFraction 56 over 15 EndFraction times one-fourth. X = StartFraction 14 over 15 EndFraction. step 1 step 2 step 3 step 4
Mathematics
2 answers:
stealth61 [152]3 years ago
8 0

Answer:

The Answer Is Step: 3

Step-by-step explanation:

I Took The Test

astraxan [27]3 years ago
6 0

Answer:

Step 3

Step-by-step explanation: trust me i took it on edge

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What are the possible values of x if (4x – 5)2 = 49?
STatiana [176]
2(4x - 5) = 49
8x - 10 = 49
8x - 10 + 10 = 49 + 10
8x = 59
8x/8 = 59/8
x = 7.375
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A high school coach needs to buy new athletic shorts for the 15 members of the basketball team. The coach must spend less than $
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If the budget is $200 and he have 15 members then we have divide the two. 200 / 15 = $13.33 per shorts. 15x =< $200. x represents 13.33. So the solution represents the coach may spend up to $13.33 per pair of shorts. If it was even 1 cent more than $13.33 than he wouldn't have enough.So he can spend up to $13.33 or less per pair of shorts.
5 0
3 years ago
Read 2 more answers
In a recently administered iq test, the scores were distributed normally, with mean 100 and standard deviation 15. what proporti
iragen [17]

To solve for proportion we make use of the z statistic. The procedure is to solve for the value of the z score and then locate for the proportion using the standard distribution tables. The formula for z score is:

z = (X – μ) / σ

where X is the sample value, μ is the mean value and σ is the standard deviation

 

when X = 70

z1 = (70 – 100) / 15 = -2

Using the standard distribution tables, proportion is P1 = 0.0228

 

when X = 130

z2 = (130 – 100) /15 = 2

Using the standard distribution tables, proportion is P2 = 0.9772

 

Therefore the proportion between X of 70 and 130 is:

P (70<X<130) = P2 – P1

P (70<X<130) = 0.9772 - 0.0228

P (70<X<130) = 0.9544

 

Therefore 0.9544 or 95.44% of the test takers scored between 70 and 130.

6 0
4 years ago
If you have 2\10 of an apple, how many fifths do you have
sukhopar [10]

Answer:

4/5

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Question
mixer [17]

The intervals are given as follows:

  • In range notation: [-282, 20,320].
  • In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}

<h3>What is the range of elements notation for interval?</h3>

The range of elements notation for interval is given by:

[a,b].

In which:

  • a is the smallest value.
  • b is the greatest value.

In this problem these values are given by:

a = -282, b = 20,320.

Hence the interval in range notation is given by:

[-282, 20,320].

<h3>How to write the interval in set-builder notation?</h3>

The same interval can be written as follows, using set-builder notation?

{x|x ∈ ℝ, a <= x <= b}

Hence, for the situation described in this problem, the set-builder notation for the values is:

{x|x ∈ ℝ, -282 <= x <= 20,320}

More can be learned about notation of intervals at brainly.com/question/27896097

#SPJ1

5 0
2 years ago
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