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marin [14]
3 years ago
14

Look at picture skjdnisujwndijbd

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

skjdnisujwndijbd

2.5 hours

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HELP PLEASE, WILL MARK BRANLIEST!!!
zhannawk [14.2K]

Answer:

144

Step-by-step explanation:

angle A + angle B = 180 (supplementary angle)

A = 4B

4b+b=180

5b=180

Divide 5 on both sides to get b=36

180-36= measure of angle A

180-36=144

4 0
3 years ago
Helppppppppppppppppppppppppppppppppppppp
almond37 [142]

i think it would be D

4 0
2 years ago
Match each operation involving f(x) and g(x) to its answer.
galben [10]
F(x)=1-x² and g(x)=√(11-4x)

(g+f)(2)=>

 1-(2)²+√(11-4(2))

=√3-3

(f/g)(-1)

(1-(-1)²)/(√(11-4(-1))

=0

(g-f)(-1)

√(11-4*-1)-(1-(-1)²

=√15

(g×f)(2)

1-(2)²×√(11-4(2))

-3√3
8 0
3 years ago
What is the reciprocal of 3 1/5
Talja [164]

Answer:

5/16

Step-by-step explanation:

We need to change the mixed number to an improper fraction to find the reciprocal

3 1/5 = (5*3+1)/5 = 16/5

The reciprocal of 16/5 is found by flipping the fraction

5/16

4 0
3 years ago
Read 2 more answers
The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during peak r
eduard

Answer:

a) height of this uniform distribution = 1/8 = 0.125.

b) P( 4 < x < 5) = (5 - 4)*0.125 = 0.125

c) P( 3 < x < 8) = (8 - 3)*0.125 = 0.625

d) P(x = 0) = 0*0.125 = 0

Step-by-step explanation:

Height of this uniform distribution is same as finding the probability for each waiting minutes.

Height of uniform distribution = 1/n. Where n is the number of occurence, in this n = 8.

a) height of this uniform distribution = 1/8 = 0.125.

Let random variable x = waiting time.

b) probability of waiting between four and five minutes

P( 4 < x < 5) = (5 - 4)*0.125 = 0.125

c) probability of waiting between three and eight minutes

P( 3 < x < 8) = (8 - 3)*0.125 = 0.625

d) probability of waiting five minutes exactly.

Since this would be just one line, and the width of the line is 0, then the

P(x = 0) = 0*0.125 = 0

8 0
3 years ago
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