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lakkis [162]
3 years ago
15

HELPPP

Mathematics
2 answers:
densk [106]3 years ago
5 0

Answer:

Step-by-step explanation:

<u><em>Decompose each number:</em></u>

<em><u /></em>6) 90 = 9 \times 10\\\\7) 40 = 4 \times 10\\\\8)890 = 89 \times 10\\\\9) 300 = 3 \times 100\\\\10) 7000 = 7 \times 1000\\\\11)3700 = 37 \times 100\\\\

<em><u>Correct the error. Write the correct decomposition:</u></em>

<em><u /></em>12) 560 = 56 \times 10\\\\13) 4300 = 43 \times 100\\\\14) 6000 = 60 \times 100 \ \ or \ \ 6 \times 1000<em><u /></em>

Crazy boy [7]3 years ago
3 0

Answer:

Decompose each number:

\begin{gathered}6) 90 = 9 \times 10\\\\7) 40 = 4 \times 10\\\\8)890 = 89 \times 10\\\\9) 300 = 3 \times 100\\\\10) 7000 = 7 \times 1000\\\\11)3700 = 37 \times 100\\\\\end{gathered}

6)90=9×10

7)40=4×10

8)890=89×10

9)300=3×100

10)7000=7×1000

11)3700=37×100

Correct the error. Write the correct decomposition:

\begin{gathered}12) 560 = 56 \times 10\\\\13) 4300 = 43 \times 100\\\\14) 6000 = 60 \times 100 \ \ or \ \ 6 \times 1000\end{gathered}

12)560=56×10

13)4300=43×100

14)6000=60×100 or 6×1000

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Part B) Makayla 300 6% quarterly  613.04Time=?
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n = 4
Years = log (total/principal) / [n * log * (1 + rate / n)]
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Years = <span> <span> <span> 11.9999044949 </span> </span> </span>

So, the difference is roughly 3 years.



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