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brilliants [131]
3 years ago
8

When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced.

Chemistry
1 answer:
Andreyy893 years ago
3 0

Answer: Thus, the number of moles of aluminum chloride could be produced from 27.0 g of aluminum is 1.0 mol.

Explanation:

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rite stepwise equations for protonation or deprotonation of this polyprotic species in water. What are the products of the first
adoni [48]

<u>Answer:</u> The products of the given chemical equation are HCO_3^-\text{ and }OH^-

<u>Explanation:</u>

Protonation equation is defined as the equation in which protons get added in the substance.

The chemical equation for the protonation of carbonate ion in the presence of water follows:

CO_3^{2-}+H_2O\rightarrow HCO_3^-+OH^-

By Stoichiometry of the reaction:

1 mole of carbonate ion reacts with 1 mole of water to produce 1 mole of hydrogen carbonate ion and 1 mole of hydroxide ion

Hence, the products of the given chemical equation are HCO_3^-\text{ and }OH^-

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3 years ago
A car manufacturer needs to assemble the maximum number of cars using the following equation: 1 body frame + 4 wheels + 2 headli
larisa [96]

The wheels will be completely used up and  it is the limiting reactant in this case.

<h3>What is a limiting reactant?</h3>

The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.

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The wheels will be completely used up and  it is the limiting reactant in this case.

Learn more about limiting reactants here: brainly.com/question/14222359

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2 years ago
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3 years ago
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What is the molarity of a solution that has 4.4 moles BaCl2 in 1.5 Liters of solution?
garik1379 [7]

Answer:

2.9 M

Explanation:

Step 1: Given data

Moles of barium chloride (solute): 4.4 moles

Volume of solution: 1.5 liters

Step 2: Calculate the molarity of barium chloride in the solution

The molarity is a way to quantitatively express the concentration of a solute in a solution. The molarity is equal to the moles of solute divided by the volume, in liters, of solution.

M=\frac{4.4mol}{1.5L} =2.9 M

7 0
3 years ago
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