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Never taste-test unless the teacher tells you to.
Do not touch anything without directions.
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Do not mishandle lab equipment.
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Act serious; no horseplay!
Report accidents to the teacher right away!
Have a great day, scholar!
Answer:
54.1 % Ca, 43.2 % O, 2.7% H
Explanation:
Molecular formula for calcium hydroxide is Ca(OH)₂
As we don't have a mass of Ca(OH)₂ to find out the percentage composition, we consider that the question refers to 1 mol of compound.
1 mol of hydroxide weighs 74.08 g
1 mol of hydroxide has 1 mol of Ca, therefore 40.08 g are Ca
2 moles of O therefore 32g are O
2 moles of H therefore 2 g are H
Percentage composition is known as (Mass of element/Total mass) . 100
(40.08 / 74.08) . 100 = 54.1 %
(32 / 74.08) . 100 = 43.2 %
(2 / 74.08) . 100 = 2.7%
im a smart one
Divide the mass of solution by total volume of the solution. formula would be C = M/V (m is mass and v is volume). include the value you found of the mass and volume, then divide them to find the concentration of your solution.