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julia-pushkina [17]
3 years ago
5

Which best describes a chain reaction associated with a nuclear reaction? Neutrons released during a fusion reaction cause other

nuclei to fuse. Neutrons released during a fission reaction cause other nuclei to split. Helium nuclei released during a fission reaction cause other nuclei to split. Helium nuclei released during a fusion reaction cause other nuclei to fuse.
Chemistry
2 answers:
atroni [7]3 years ago
8 0
The statement that describes a chain reaction brought about by a nuclear reaction is "neutrons <span>released during a fission reaction cause other nuclei to split." This is applicable to fission reactions only wherein atoms split and produce neutrons that also cause further atoms to split, thus creating a chain or series of reactions.</span>
alexdok [17]3 years ago
3 0

Answer:

B

Explanation:

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If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

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The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

n = 0.622 / molar mass (n = Avogardos number)

Molar mass =  7.18 g

Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g

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What is the % yield if 20 grams of hydrogen is reacted with 32 grams
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The half-life of argon-39 is 269 years. It decays into krypton-39. After 1,076 years, what fraction of the original amount of ar
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From the question given above, the following data were obtained:

Half-life (t½) = 269 years

Time (t) = 1076 years

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Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 269 years

Time (t) = 1076 years

Number of half-lives (n) =?

n = t / t½

n = 1076 / 269

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the fraction of the original amount remaining. This can be obtained as follow:

Let N₀ be the original amount.

Let N be the amount remaining.

Number of half-lives (n) = 4

Fraction remaining (N/N₀ ) =?

N = 1/2ⁿ × N₀

N = 1/2⁴ × N₀

N = 1/16 × N₀

Divide both side by N₀

N/N₀ = 1/16

Thus, the fraction of the original amount remaining is 1/16

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