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MissTica
2 years ago
11

Fill in the coefficients that will balance the following reaction: a0Zn + a1Fe(NO3)2 → a2ZnNO3 + a3Fe

Chemistry
2 answers:
Sonja [21]2 years ago
5 0

2Zn + Fe(NO3)2 -> 2Zn(NO3)2 + Fe.

In other words: coefficients for a0 and a2 are 2, a1 and a3 are blank/0.

kramer2 years ago
4 0
Zn + Fe(NO3)2 -> Zn(NO3)2 + Fe
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A gaseous compound has a mass of 8.00 g at 2.81 atm and 300. K in a 1.00 L container.
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Answer:

The question asks for moles, which can be obtained from P-V-T data using the ideal gas

equation: n =

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Now use the rearranged gas law to determine the number of moles in the sample:

!

n = PV

RT = (6.47 x 105 Pa)(5.65 x 10-4m3

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(8.314 J

mol K )(21.7 + 273.15 K) = 0.149 mol.

All conditions except the pressure and volume are fixed, so P1V1 = P2V2 can be used: 3.62 L

101kPa

(647 kPa)(0.565 L)

2

1 1

2 = =

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PV V

Explanation:

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0.90 g of sodium hydroxide ( NaOH ) pellets are dissolved in water to make 3.0 L of solution. What is the pH of this solution
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Explanation:

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2 years ago
The atomic number determines the identity of the atom. True or False?
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THE CORRDCT ANSWER IS TRUE
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C) Solar energy is the source of all forms of energy.give reasons​
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2. Consider the reaction 2 Cg H18 (4) +250â (9) ⺠16 co, (g) + 18 HâO(g) la How many moles of H20co) are produced, when |--16:1
Sladkaya [172]

Answer :

(a) The moles of water produced are 145.35 moles.

(b) The mass of oxygen needed are 3080.8 grams.

<u>Solution for part (a) : Given,</u>

Moles of C_8H_{18} = 16.15 moles

First we have to calculate the moles of H_2O

The balanced chemical reaction is,

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

From the balanced reaction we conclude that

As, 2 moles of C_8H_{18} react to give 18 moles of H_2O

So, 16.15 moles of C_8H_{18} react to give \frac{16.15}{2}\times 18=145.35 moles of H_2O

The moles of water produced are 145.35 moles.

<u>Solution for part (b) : Given,</u>

Mass of C_8H_{18} = 878 g

Molar mass of C_8H_{18} = 114 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_8H_{18}.

\text{ Moles of }C_8H_{18}=\frac{\text{ Mass of }C_8H_{18}}{\text{ Molar mass of }C_8H_{18}}=\frac{878g}{114g/mole}=7.702moles

Now we have to calculate the moles of O_2

The balanced chemical reaction is,

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

From the balanced reaction we conclude that

As, 2 moles of C_8H_{18} react with 25 moles of O_2

So, 7.702 moles of C_8H_{18} react with \frac{7.702}{2}\times 25=96.275 moles of O_2

Now we have to calculate the mass of O_2.

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(96.275moles)\times (32g/mole)=3080.8g

The mass of oxygen needed are 3080.8 grams.

6 0
2 years ago
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