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3 years ago

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Mathematics

1 answer:

fredd [130]3 years ago

6 0

Answer: rise will be drawing a straight verticle line, run will be a straight horizontal line, and the slope is y=x+2

Step-by-step explanation:

You might be interested in

Simplify radical of 27

olga55 [171]

Yo mean sqrt 27 or √27

remember
√(xy)=(√x)(√y)

√27=(√9)(√3)=(3)(√3)=3√3

8 0

4 years ago

The temperature of a liquid in an experiment changes by −10.4°F from the beginning of the experiment to the first check. After m

ziro4ka [17]

Answer: 63.5 F

Step-by-step explanation:

you are correct up there I took the test and it was correct

3 0

3 years ago

Find the gradient of the line segment between the points (-5,2) and (4,3) give your answer in the simplest form

Leokris [45]

Answer: The gradient of the line segment between the points (-5,2) and (4,3) is $\dfrac{1}{9}$ .

Step-by-step explanation:

Formula for gradient of a line segment :

$\text{Gradient}=\dfrac{\text{Difference between y-coordinates}}{\text{Difference between x-coordinates}}$

Given points of the line segment: (-5,2) and (4,3)

$\text{Gradient} =\dfrac{3-2}{4-(-5)}$

$\text{Gradient} =\dfrac{1}{4+5)}$

$\text{Gradient} =\dfrac{1}{9}$

Therefore , the gradient of the line segment between the points (-5,2) and (4,3) is $\dfrac{1}{9}$ .

7 0

3 years ago

What is usually the highest percentage of family income that lenders allow for monthly mortgage payments

bonufazy [111]

I would say about 28%. this would include the mortgage principal, mortgage interest , and all taxes and home insurance. hope this helped

3 0

3 years ago

Find the equation for the set of points whose distance from the y-axis equals the distance from the xz-plane.

julia-pushkina [17]

Answer:

$x_1^2 + z_1^2 = y_1^2$

Step-by-step explanation:

Let $p(x_1, y_1, z_1)$ be the point.

Any point on y-axis is (0, y, 0)

So, distance is

= $\sqrt{x_1^2+0 + z_1^2}$

= $\sqrt{x_1^2 + z_1^2}$ ......(1)

Now any point on x-z plane is $( x_1, 0, z_1 )$

Distance from p to this point is

= $\sqrt{0+y_1^2 + 0}$

= $\sqrt{y_1^2}$ .........(2)

Equating (1) and (2), we get

$\sqrt{x_1^2 + z_1^2} = \sqrt{y_1^2}$

$x_1^2 + z_1^2 = y_1^2$

This is the required equation.

8 0

3 years ago