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Goryan [66]
3 years ago
11

Help me with this question plz

Mathematics
1 answer:
Dvinal [7]3 years ago
6 0

Answer:

4

Step-by-step explanation:

4x +8 = 7x -4

3x = 12

x = 4

pls mark brainiest :)

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33.3 the 3 on the right of deci being the tenth

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How many times will interest be added to the principal in 1 year if the interest is compounded annually?
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Annually means once a year so if it is compounded annually then it is compounded only once per year, meaning interest is added to principal only 1 time per year.

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Find the distance and midpoint for the following coordinates.<br> P(7.6 , 10.1) and Q(4.6 , 3.1)
KATRIN_1 [288]
Solving for the midpoint:

x - coordinate: (7.6 + 4.6)/2 = 6.1
y - coordinate: (10.1 + 3.1)/2 = 6.6

Midpoint: (6.1 , 6.6)

Solving for the distance:

Distance formula: sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

D = sqrt( (7.6 - 4.6)^2 + (10.1 - 3.1)^2 <span>)
D = sqrt( 3^2 + 7^2)
D = sqrt(58)
D = 7.62 units

Distance = 7.62 units</span>
8 0
3 years ago
it's asking me to find an equation for the line I drew but I don't know how, and I'm not even sure if my line is correct.
vovangra [49]
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y =  \frac{15}{2} x
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Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4&#10;


draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
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