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3 years ago

Look at the picture to see the question.

Mathematics

1 answer:

Andru [333]3 years ago

6 0

Answer:

y = 5/7x + 5

Step-by-step explanation:

If you replace the x and y in the equation with points x and y of point (35, 30) and change the 10 to b you can solve for b which is the what changes from the original equation to this one.

30 = 5/7(35) + b

30 = 25 + b

5 = b

Since the equations are parallel they have the same slope.

This is the equation for a parallel line that passes through point (35, 30):

y = 5/7x + 5

Hope this made sense! Please give Brainliest!

You might be interested in

Solve for y:<br> x + 2y = -8<br><br> y=-1/2x+4<br> y=-1/2x-4<br> y=-2x - 4<br> y=1/2x-4

adelina 88 [10]

Answer:

x + 2y = -8 = y = -4 - 1/2x

y= -1/2x + 4 = y = 4

y= -1/2x - 4 = y = -4

y=-2x - 4 = y = -4

y=1/2x-4 = y = -4

Step-by-step explanation:

(x + 2y = -8 = y = -4 - 1/2x)

$x+2y=-8\\2y=-8-x\\y=-4-\frac{1}{2}x\\$

4 0

2 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago

a pool is being filled with a large water hose. the height of the water in a pool is determined by 7g^2+3g-4. Previously the poo

ArbitrLikvidat [17]

If both the hoses are on the same time then the height of the water in the pool is given by the expression 15g^2 + 5g - 6

Step-by-step explanation:

(7g^2 + 3g - 4) + (8g^2 + 2g - 2)

= (7g^2 + 8g^2) + ( 3g + 2g) + (-4 -2)

with the help of distribution law,

= (7 +8)g^2 + (3 + 2)g - (4 + 2)

= 15g^2 + 5g - 6

Therefore if both the hoses are on the same time then the height of the water in the pool is given by the expression 15g^2 + 5g - 6

3 0

3 years ago

If line lis parallel to line m, find the value of x and y. (please help taking a test)

castortr0y [4]

Answer:

x=8 and y=21

Step-by-step explanation:

12x-28=7x+12 (the 2 angles are equivalent)

12x-7x=12+28

5x=40

x=8

9y-77 + 12x-28 =180 (the sum of those 2 angles is a flat angle (180°))

9y-77+12*8-28=180

9y=180+28+77-96

9y=189

y=21

3 0

3 years ago

Pedro bought 7 tickets to a basketball game. He paid a total of $147. Enter an equation, using x as your variable, to determine

VladimirAG [237]

Answer:

7 . x = 147

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers