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3 years ago

14

Find The Angle (See Image)

1 answer:

AnnZ [28]3 years ago

8 0

Answer:

do you how many there is 5 angles if thats what ur asking

Step-by-step explanation:

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Please help me guys please I’m stuck on this

n200080 [17]

Answer:

68. See pic

Step-by-step explanation:

8 0

3 years ago

Describe how to find the sums -4 + 2 and -4 + -2 on a number line

xz_007 [3.2K]

For number 1, you start at zero and go to the left since the four is negative four spaces. Then, you go to the right two spaces since the 2 is positive. Your answer is -2

For number 2, you start at zero and go left four spaces since it is negative and then go two more spaces to the left because it is negative again

7 0

3 years ago

A game starts by flipping a coin. If you get heads, then you get to roll a die and, if you roll a 4, you win the jackpot. If you

Mariana [72]

$\frac{5}{24}$

Step-by-step explanation:

There are two ways to win a jackpot.

Let $p_{1}$ be the probability for first method and $p_{2}$ be the probability for second method.

Probability to get a head= $p_{head}$ = $\frac{1}{2}$

Probability to get a $4$ in the die= $p_{4}$ $=\frac{1}{6}$

Probability to get a head and get a 4 in die=[ $p_{1}$ tex]p_{head}\times p_{4}[/tex]= $\frac{1}{2}\times \frac{1}{6} =\frac{1}{12}$

Probability to get a tail= $p_{tail}$ = $\frac{1}{2}$

Probability to get a heart= $p_{heart}$ = $\frac{13}{52} =\frac{1}{4}$

Probability to get a tail and get a heart in the deck= $p_{tail} \times p_{heart}$ = $\frac{1}{2}\times \frac{1}{4}=\frac{1}{8}$

Total probability to win a jackpot= $p_{1}+p_{2}=\frac{1}{12}+\frac{1}{8}=\frac{5}{24}$

So,probability to win a jackpot is $\frac{5}{24}$

3 0

4 years ago

Dominik [7]

I think the answer is C hope this helps

7 0

3 years ago

3<br>Find the value of a <br>in the equation,(3+4√3)(2-a√3)=-18+2√3

ankoles [38]

Given:

The equation is:

$\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}$

To find:

The value of a.

Solution:

We have,

$\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}$

On simplification, we get

$(3)(2)+(4\sqrt{3})(2)+(3)(-a\sqrt{3})+(4\sqrt{3})(-a\sqrt{3})=-18+2\sqrt{3}$

$6+8\sqrt{3}-3a\sqrt{3}-4a(3)=-18+2\sqrt{3}$

$6+8\sqrt{3}-3a\sqrt{3}-12a=-18+2\sqrt{3}$

$(6-12a)+(8-3a)\sqrt{3}=-18+2\sqrt{3}$

On comparing both sides, we get

$6-12a=-18$

$-12a=-18-6$

$a=\dfrac{-24}{-12}$

$a=2$

And,

$8-3a=2$

$-3a=2-8$

$a=\dfrac{-6}{-3}$

$a=2$

Therefore, the value of a is 2.

3 0

3 years ago