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atroni [7]
3 years ago
5

Nonstandard dice can produce interesting distributions of outcomes. you have two balanced, six-sided dice. one is a standard die

, with faces having 1, 2, 3, 4, 5, and 6 spots. the other die has three faces with 0 spots and three faces with 6 spots. what are the possible values for the total number of spots y on the up-faces when you roll these two dice?
Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0
<span>1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
   
One die can show the values 1-6, while the other die can only show 0 or 6. So the possible totals are 1 through 6 plus 0 and 1 through 6 plus 6. Written out, one-by-one, this gives: 1+0 = 1 2+0 = 2 3+0 = 3 4+0 = 4 5+0 = 5 6+0 = 6 1+6 = 7 2+6 = 8 3+6 = 9 4+6 = 10 5+6 = 11 6+6 = 12</span>
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Four friends evenly split the cost of miniature golf.They each paid five dollars.How much did it cost to play miniature golf?
kap26 [50]

Answer:

It costed $20 dollars in total

Step-by-step explanation:

5 0
3 years ago
Step by step workout of ;<br> log x^3+log 5x=5 log 2-log 2/5
Charra [1.4K]

Answer:

x = 2

Step-by-step explanation:

log  \: {x}^{3}  + log \: 5x = 5log \: 2 - log \:  \frac{2}{5}  \\  \\  \therefore \: log( {x}^{3}  \times 5x) = log  {2}^{5} - log \:  \frac{2}{5}  \\  \\ \therefore \: log( 5{x}^{4}) = log 32 - log \:  \frac{2}{5} \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(32  \times  \frac{5}{2}  \bigg) \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(16  \times  5) \\  \\ \therefore \: 5{x}^{4}=  16  \times  5 \\  \\ \therefore \: {x}^{4}=   {2}^{4}   \\  \\  \huge \purple{ \boxed{\therefore \: {x} = 2}}

4 0
3 years ago
Simplify 6(1/4+5/2)-2
zysi [14]
6(0.25+2.5)-2
6(2.75)-2
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7 0
4 years ago
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When coverting centimeters to inches,do you multiply or divide by 2.54?Explain. If someone Explains and gets it correct tell me
sukhopar [10]

Answer:

Divide by 2.54

Step-by-step explanation:

Because a centimeter is smaller than an inch, you have to divide by 2.54 when converting from cm to inches.

7 0
2 years ago
How is the Distributive Property used to simplify operations with scientific notation
Citrus2011 [14]

Answer:

See explanation

Step-by-step explanation:

Let a,b, and c be real numbers.

The distributive property says that:

a(b + c) = ab + ac

Assuming we want to simplify:

10(5*10^{-1}+150*10^{-3})

We apply the distributive property to get:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10+150*10^{-3} \times 10

We can now use rules of exponents to simplify further:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10^{1} +150*10^{-3} \times 10^{1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1 + 1} +150*10^{-3 + 1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{0} +150*10^{-2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2}x {10}^{2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2 + 2}

10(5*10^{-1}+150*10^{-3}) = 5+1.50*10^{0} = 6.5 \times  {10}^{0}

4 0
3 years ago
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