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Setler79 [48]
3 years ago
5

Solve from missing angle​

Mathematics
1 answer:
kari74 [83]3 years ago
6 0
Are there any answer choices? If not, when i worked it out i got ≈22.8
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You are a male who has a high school diploma. You plan to attend college and earn a bachelor’s degree. When you graduate from co
blsea [12.9K]

Answer:

Answer: 11,272

Step-by-step explanation: there are 52 weeks in a year multiplied by the median wage, which is 1001. Then minus 40,780.

Step-by-step explanation:

HOPE THIS HELPS!!!!!! :D

7 0
2 years ago
Find the standard equation for the circle having the given center and radius.
RoseWind [281]

\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{0}{h}~~,~~\underset{0}{k})}\qquad \stackrel{radius}{\underset{7}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - 0 ~~ )^2 ~~ + ~~ ( ~~ y-0 ~~ )^2~~ = ~~7^2\implies x^2+y^2=49

7 0
2 years ago
One hose can fill a small swimming pool in 65 minutes. A larger hose can fill the pool in 35 minutes. How long will it take the
tatuchka [14]

Answer:

22.75 minutes or 22 minutes 45 seconds

Step-by-step explanation:

Okay, this is a working together question. Let’s walk through it together!

Firstly, let’s say the total volume of the swimming pool is x sq.meters

Now, the rate of the smaller hose would be x/65 while that of the larger will be x/35

Now, their combined rate would be x/65 + x/35 = 100x/2275

Now, since the volume is x, the time taken is simply, the volume divided by the joint rate. That is mathematically equal to x divided by 100x/2275

x * 2275/100x = 2275/100 = 22.75 minutes or 22 minutes 45 seconds

8 0
3 years ago
How do I resolve this? <br> Como resuelvo esto?
Nikolay [14]

\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ -----\\ A=144\pi  \end{cases}\implies 144\pi =\pi r^2\implies \cfrac{144\pi }{\pi }=r^2 \\\\\\ 144=r^2\implies \sqrt{144}=r\implies \boxed{12=r} \\\\\\ \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad C=2\pi \boxed{12}\implies C=24\pi

4 0
3 years ago
I'd really appreciate some help on these questions, I'm really struggling
nikklg [1K]
We can use linear combinations of the equations to eliminate variables.

3x - 4y = 1
-2x + 3y = 1

To eliminate y we'll make the linear combination of 3 times the first equation minus four times the second. 

9x - 12y = 3
-8x + 12y = 4

Adding,
x = 7

We could solve for y directly but let's use another linear combination, twice the first plus three times the second:

2(3x - 4y) + 3(-2x + 3y)= 2(1)+3(1)

y = 5

Check: 3(7)-4(5)=1 good.   -2(7)+3(5)=1 good.

Q18 Answer: (7,5)

y = -3x + 5
5x - 4y = -3

4y +1(5x - 4y) = 4(-3x + 5) + 1(-3)

5x = -12x + 20 -3

17 x = 17

x = 1
y = -3(1) + 5 = 2
Check: 5(1) - 4(2) = -3 good

Q19 Answer (1,2)

6x + 5y = 25
x = 2y + 24
6x = 12y + 144
5y = 25 - 12y - 144
17y = -119
y = -119/17= -7
x = 2y+24= 10
Check: 6(10)+5(-7)=25 good   2y+24=2(-7)+24=10=x good

Q20 Answer (10,-7)


3x + y = 18
-7x + 3y = -10
9x  + 3y = 54
9x - -7x = 54 - -10
16x = 64
x=4
y = 18 -3x = 18-12=6

Check: 3(4)+6=18 good,  -7(4)+3(6)=-10 good

Q21 Answer: (4,6)

6 0
3 years ago
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