Answer:
No
Step-by-step explanation:
Answer:
vbvcfvbnbvcxcvbnvcxvbnmbvcvbvfdfgbhnbgvfgvbnbgfghbnbgvfgvbnbgfgbngfgbgfgfgfgfgfgfgfgfgfgfgrrrdrd
Step-by-step explanation:
Answer:
No
Step-by-step explanation:
If y is a function of x, then the equation would be written as a "y =" equation, not an "x = " equation. This example is one where x is a function of y.
Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Answer:
It is 9x^3.
Step-by-step explanation:
36x^4 and 45x^3.
GCF of 36 and 45 = 9
GCF of x^4 and x^3 = x^3
GCF of 36x^4 and 45x^2 = 9x^3.
