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Stells [14]
3 years ago
14

A b or c ? Help please

Mathematics
2 answers:
klasskru [66]3 years ago
6 0

Answer:

Center: (−3,2)

Radius: 3

Step-by-step explanation:

horsena [70]3 years ago
3 0

Answer:

The second one I think

Step-by-step explanation:

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Solve the system of equations.<br><br><br> −5x+2y=9<br> y=7x<br> ​
RUDIKE [14]

Answer:

x=1  y=7

Step-by-step explanation:

−5x+2y=9

y=7x

Substitute the second equation into the first

-5x +2(7x) = 9

Distribute

-5x +14x = 9

Combine like terms

9x=9

Divide by 9

9x/9 =9/9

x= 1

Now find y

y = 7(1)

y = 7

5 0
3 years ago
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Find the solutions of the quadratic equation <img src="https://tex.z-dn.net/?f=-x%5E2%2B7x-14%3D0" id="TexFormula1" title="-x^2+
Vinvika [58]

Answer:

Step-by-step explanation:

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3 0
2 years ago
7% of what lenght is 200 ft?
Nastasia [14]
If you would like to solve 7% of what length is 200 ft, you can calculate this using the following steps:

7% of what length is 200 ft
7% * x = 200
7/100 * x = 200      /*100/7
x = 200 * 100 / 7
x = 2857 ft

Result: 7% of 2857 ft is 200 ft.
5 0
3 years ago
Read 2 more answers
Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

3 0
3 years ago
Which of the following is the equation of a line perpendicular to the line, , passing through the point (3,9)?
julsineya [31]
Y = -3/2x + 4...slope is -3/2
A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So that means the slope we will need is 2/3...see how I flipped the slope and changed the sign.
Now we use y = mx + b....slope(m) = 2/3....(3,9)...x = 3 and y = 9.
Time to sub...we r looking for b, the y intercept.

9 = 2/3(3) + b
9 = 2 + b
9 - 2 = b
7 = b 

so the perpendicular equation is : y = 2/3x + 7...but we need it in Ax + By = C form....
y = 2/3x + 7....multiply by common denominator of 3 to get rid of fractions
3y = 2x + 21...subtract 2x from both sides
-2x + 3y = 21....<== ur answer...normally, I would have multiplied this by -1 to make x positive...but that is not an answer choice
5 0
3 years ago
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