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Varvara68 [4.7K]
4 years ago
10

Please help!

Mathematics
1 answer:
ANEK [815]4 years ago
8 0

Answer: 315 miles

Step-by-step explanation:

21 times 15

its 315

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vichka [17]
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3 years ago
The sum of five consecutive multiples of 4 is 20.Find the smallest integer.
Aloiza [94]

Answer:

The smallest integer is -4.

Step-by-step explanation:

Let the smallest integer be x.

Since the integers are all multiples of 4, they are

=> x, x+4, x+8, x+12 and x+16

=> x + x+4 + x+8 + x+12 + x+16 = 20

=> 5x + 40 = 20

Subtract 40 from both sides of the equation

5x +40 - 40 = 20 - 40

5x = -20

Divide both sides by the coefficient of x(which is 5)

\frac{5x}{5} = \frac{-20}{5}

x = -4

∴ the smallest integer is -4.

Hope this helps!!!

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Can a pair of numbers have more than one common factor?
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Rewrite the equation in Ax+By=C form
Ksju [112]

Ax + By = C form of the given equation is –6x + y = –28.

Solution:

Given equation is y – 2 = 6(x – 5).

To write the equation in Ax + By = C format:

y – 2 = 6(x – 5)

y – 2 = 6x – 30

Add 2 on both sides of the equation.

y – 2 + 2 = 6x – 30 + 2

y = 6x – 28

Subtract 6x from both sides of the equation.

y – 6x = 6x – 28 – 6x

y – 6x = –28

Arrange the terms in the equation.

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This is in the form of Ax + By = C.

Here A = –6, B = 1 and C = –28.

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Name the following segment or point
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