The equation to be solved is: 3 [ 2 ^ (2t - 5) ] - 4 = 10
The steps are:
1) transpose - 4=> 3 [ 2^ (2t - 5) ] = 10 + 4
2) Combine like terms => 3 [2^ (2t - 5) ] = 14
3) Divide both terms by 3 => 2^ (2t - 5) = 14 / 3
4) Take logarithms of both sides => (2t - 5) log (2) = log (14/3)
5) Divide both sides by log (2) =>
log (14/3)
2t - 5 = -------------------
log (2)
6) transpose - 5+>
log (14/3)
2t = ------------------- + 5 = 2.22 + 5
log (2)
2t = 7.22
7) divide both sides by 2 => t = 7.22 / 2 = 3.61
5x+3x+7x=180
15x=180
x=12
5(12)=60
3(12)=36
7(12)=84
I think b positive let me know if it is correct
Answer:
A
C
D
Step-by-step explanation:
I copied some smart kid
Answer:
x = 2
Step-by-step explanation:
Using the rules of logarithms
• log 
⇔ nlog x
• log x + log y ⇔ log(xy)
• log x = log y ⇒ x = y
Given
3 ln2 + ln8 = 2ln(4x)
ln2³ + ln8 = ln(4x)²
ln8 + ln8 = ln16x²
ln(8 × 8) = ln16x²
ln64 = ln16x², hence
16x² = 64 ( divide both sides by 16 )
x² = 4 ( take the square root of both sides )
x = 
= 2
