Answer:
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Explanation:
to prevent others from viewing it
Answer:
Using Python language :
a = eval ( input ( "Enter a mark please"))
if ( a <0){
print ("Invalid mark")};
else if (a >=90 && a <=100){ print
( "GREAT")};
Explanation:
Answer:
Explanation:
For the Program plan:
1. Two lists are structurally equal if they have the same list structure, although their atoms may be different.
2. So we are going to write a function that will check if elements in both lists at same position are atoms or not.
3. If yes then it should return true else false.
Program:
#lang scheme
( define (structurally-equal list1 list2)
(cond ((and (null? list1) (null? list2)) #t)
((or (null? list1) (null? list2)) #f)
((and (atom? (car list1)) (atom? (car list2)))
(structurally-equal (cdr list1) (cdr list2)))
((or (atom? (car list1)) (atom? (car list2))) #f)
(else (and (structurally-equal (car list1) (car list2))
(structurally-equal (cdr list1) (cdr list2) )))))
( define (atom? x) (not (or (pair? x) (null? x))))
