Answer:
Angle = Ф =
(0) = 0
Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.
Step-by-step explanation:
Given vector r(t) = 
As we know that,
velocity vector = v = 
Implies that
velocity vector = 
As acceleration is velocity over time so:
acceleration vector = a = 
Implies that
vector a =

vector a = 
Now scalar product of position vector r and acceleration vector a:
r. a = 
r.a = 
r.a = 0
Now, for angle between position vector r and acceleration vector a is given by:
cosФ =
= 
Ф =
(0) = 0
Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.
Answer:
(18,−21)
Step-by-step explanation:
Dilation: multiply each coordinate
(x,y)\rightarrow (3x,3y)
(x,y)→(3x,3y)
Dilations multiply by scale factor
(\color{red}{6},\color{blue}{-7}) \rightarrow (3\cdot \color{red}{6},3\cdot \color{blue}{-7})=\mathbf{(18,-21)}
(6,−7)→(3⋅6,3⋅−7)=(18,−21)
There are fourty one tens.
The answer is here. Hope I did help you.
Answer:
D) -0.87
Step-by-step explanation:
I took this test don't quote me on the answer but this is what my peers put.